you do 185 J of work pulling a cart

up a ramp. if the ramp does 153 J of work,what is the efficient of the ramp?
A)82.7 percent
B)121.0 percent
C)32.0 percent
D)338.0 percent

what is 153/185 ? Technically, the ramp does not do work, it absorbs energy (work) as friction.

Your putting pressure and weight on the ramp so technically the ramp is working.

It’s A

The answers for the full test are
1.A
2.C
3.A
4.A
5.D

Test answers

B
C
A
A
D

To determine the efficiency of the ramp, you need to divide the work done by the ramp by the total work done on the cart, and then multiply by 100 to express it as a percentage.

The total work done on the cart is given as 185 J, and the work done by the ramp is 153 J.

Efficiency = (Work done by ramp / Total work done) * 100

Efficiency = (153 J / 185 J) * 100

Efficiency ≈ 82.7 percent

Therefore, the correct answer is option A) 82.7 percent

oh and I think the answer is 121.0 if not then it might be 82.7