what is the sqaure root of -3/2*81
AoPS such a hypocrit3
AoPS yells at people for asking answers
Why would Aops need answers...
AoPS, please. Don't yell at people for using this website like they're supposed to, then asking questions yourself. That's just hypocritical.
√(-3/2 * 81) = 9√(3/2) i
√(-3/(2*81)) = 1/9 √(3/2) i = 1/(3√6) i = 1/18 √6 i
To find the square root of a number, we'll follow these steps:
Step 1: Simplify the expression inside the square root if possible.
In this case, let's simplify the expression:
-3/2 * 81 = -3/2 * 81/1 = -3 * 81/2 = -243/2
Step 2: Determine the value of the square root.
The square root of a negative number results in an imaginary number, denoted by "i."
So, the square root of -243/2 is (√(-243/2)) or (√(243/2) * i).
Step 3: Simplify the square root.
Let's break down the square root of 243/2.
We can separate 243 into two factors of 81 and 3:
√(81 * 3/2) = √(81) * √(3/2).
The square root of 81 is 9:
9 * √(3/2).
The square root of 2 cannot be simplified further, so the final answer is:
9 * √(3/2) or 9√(3/2).