according to ohms law what is the resistance of a lightbulb if that applied voltage is 21.0 V and the current is 3.0 amps?
24 ohms
7.0 ohms**
18 ohms
3.0 ohms
E = i R
21 = 3 R
R = 7 Ohms
correct
thx
ello
elol
elolol
thanks ig
needed to fix my name
To determine the resistance of a lightbulb using Ohm's Law, you need to use the formula V = I * R.
V represents the applied voltage, which is given as 21.0 V in this case.
I represents the current flowing through the lightbulb, given as 3.0 amps.
R represents the resistance of the lightbulb, which is the unknown in this case.
Rearranging the formula, we have R = V / I.
Substituting the given values into the formula, we get R = 21.0 V / 3.0 amps.
Evaluating this expression, we find R = 7.0 ohms.
Therefore, the resistance of the lightbulb is 7.0 ohms, so the correct answer is B: 7.0 ohms.