If 500 J of work are required to carry a charged particle between two points with a potential difference of 40V, the magnitude of the charge on the particle is:
a) 0.040 C
b) 12.5 C
c) 20C
D) cannot be computed unless the path is give
e) none of these
My solution:
I used the equation V=W/q inorder to solve for the charge. I plugged in the numbers to get 40= (500)/X. The answer I got was .08. According to the book the answer is 12.5 C
The potential difference between two points is 100V. If 2 C is transported from one of these points to the other, the magnitude of work done is:
a) 200J
b) 100 J
c) 50J
d) 100 J
e) 2 J
The solution I figured would use the same equation because involves potential difference and charge. When I calculated the answer using V=W/q I came up with the answer I came up with A 200J.
Am I handling these problems right because in the second question my answer was right but not in the first one.
Since 40 = 500/X, then X = 500/40 = 12.5 C
Your math is unique.
QV= energy
Q= 500/40 Coulombs That is not .08C
The second is correct. QV=W
In fact q= W/ V
This is q= 500J/40V
so, q= 12.5J/V or 12.5 Coulombs (C)
good
3aaaaaaaaaaaaaaaaaaash
gvch
Well, it seems like you made a calculation error in the first question. The correct calculation should be 500/40 = 12.5 C. So, the answer is indeed option b) 12.5 C.
As for the second question, your calculation is correct. The equation QV = W can be rearranged to solve for W, which gives W = QV. Plugging in the values, we get W = 2 C * 100 V = 200 J. So, the answer is indeed option a) 200 J.
It seems like you're handling these problems just fine, but be careful with your calculations! Sometimes math can be a bit of a tricky clown.
In the first question, you made an error in your calculation. The equation you used, V=W/q, is correct. However, when you rearranged the equation to solve for q, you made a mistake.
The correct calculation should be:
40 = 500/q
To isolate q, you need to divide both sides of the equation by 40:
40/40 = 500/q
1 = 500/q
Now, cross multiply:
q = 500
So, the magnitude of the charge on the particle is 500 C, which is not one of the options given. Therefore, none of the provided answer choices is correct for this question.
In the second question, your approach and calculation are correct.
Given: V = 100V, q = 2C
Using the same equation, V=W/q, you can solve for W:
100 = W/2
To isolate W, you multiply both sides of the equation by 2:
100 * 2 = W
W = 200 J
So, the magnitude of the work done is 200 J, which matches the answer choice (a) 200J.
Therefore, your approach and calculation were correct for the second question but not for the first question.