Find the sum of the first eight terms of a linear sequence whose first term is 6 and last team is 46.
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Recall that the sum of n terms is
Sn = n/2 (first+last)
208
To find the sum of the first eight terms of a linear sequence, we can use the formula for the sum of an arithmetic series:
S = (n/2)(a + l)
Where:
S is the sum of the terms,
n is the number of terms,
a is the first term, and
l is the last term.
In this case, we have:
n = 8 (since we want the sum of the first eight terms),
a = 6 (since the first term is 6), and
l = 46 (since the last term is 46).
Plugging these values into the formula, we get:
S = (8/2)(6 + 46)
= 4(52)
= 208
Therefore, the sum of the first eight terms of the linear sequence is 208.