A store is dropped from the top of a Cliff. It is seen to hit the ground below after 3.55s.How high is the cliff?
h=1/2 g t^2
solve for h.
Thank you :)
whats answer
6ix9ine
To determine the height of the cliff, we can use the formula for vertical displacement:
d = (1/2)gt^2
where:
d = vertical displacement (height of the cliff)
g = acceleration due to gravity (approximately 9.8 m/s^2)
t = time (3.55 seconds)
Plugging in the values into the formula:
d = (1/2)(9.8)(3.55^2)
d = (1/2)(9.8)(12.6)
d = (4.9)(12.6)
d = 61.74 meters
Therefore, the height of the cliff is approximately 61.74 meters.