Calculate the no. of grams of NaOH req. to absorb volume of the CO2 gas produce as Na2CO3
To calculate the number of grams of NaOH required to absorb a given volume of CO2 gas produced as Na2CO3, you need to know the reaction stoichiometry and the molar masses of the compounds involved.
First, let's write the balanced equation for the reaction in question:
Na2CO3 + 2HCl -> 2NaCl + H2O + CO2
From the balanced equation, you can see that 1 mole of Na2CO3 reacts with 2 moles of CO2.
Next, identify the molar mass of Na2CO3 and CO2:
Na2CO3: 2(22.99 g/mol) + 12.01 g/mol + 3(16.00 g/mol) = 105.99 g/mol
CO2: 12.01 g/mol + 2(16.00 g/mol) = 44.01 g/mol
Now, let's assume you know the volume of CO2 gas produced. Convert the volume to moles using the ideal gas law equation:
moles of CO2 = (volume of CO2 gas) / (molar volume of gas at standard conditions)
Finally, use the molar ratios from the balanced equation to calculate the moles of Na2CO3 and then convert to grams:
moles of Na2CO3 = (moles of CO2) / 2
grams of Na2CO3 = (moles of Na2CO3) x (molar mass of Na2CO3)
By following these steps, you'll be able to determine the number of grams of NaOH required to absorb the volume of CO2 gas produced as Na2CO3.