A man uses a crowbar 1.5 meters long to lift a rock weighing 600N
(Newtons). If the fulcrum is 0.50
Meter fromthe end of the bar touching the rock,how much effort
The man should apply?
the man is twice as far from the fulcrum as the rock
so the effort is half the weight of the rock
To find the effort the man needs to apply, we can use the principle of moments. The principle of moments states that the total clockwise moments around a point and the total anticlockwise moments around the same point are equal.
In this case, the total clockwise moment is equal to the total anticlockwise moment. The clockwise moment is the product of force and distance, while the anticlockwise moment is the product of the force applied by the man and the distance from the fulcrum.
Let's denote the effort force applied by the man as 'E'. The force applied by the rock is 600N, and the distance from the fulcrum to the rock is 0.50 meters. The distance from the fulcrum to the effort force is 1.5 - 0.50 = 1 meter.
Now, we can set up the equation using the principle of moments:
Clockwise moment = Anticlockwise moment
(600N) * (0.50m) = E * (1m)
Rearranging the equation to solve for E:
E = (600N * 0.50m) / (1m)
E = 300N
Therefore, the man should apply an effort force of 300 Newtons to lift the rock using the crowbar.