A swimming pool of width 9.0 m and lenght 24.0 mis filled with water to a deepth of 3.0 m force 1215 m.Calculate pressure on the bottom of the pool due to the water
I m not satisfied with your answer. It's not helped me in any way. Sorry but it's right....
Sorry to say but this answer is incorrect
To calculate the pressure on the bottom of the pool due to the water, we can use the equation:
Pressure = Force/Area
First, let's calculate the force exerted by the water on the bottom of the pool. We can use the formula:
Force = Weight
The weight of the water is equal to the mass of the water multiplied by the acceleration due to gravity. The mass of the water can be calculated using its density and volume:
Mass = Density * Volume
The density of water is 1000 kg/m³, and the volume can be calculated by multiplying the width, length, and depth of the pool:
Volume = Width * Length * Depth
Plugging in the given values:
Volume = 9.0 m * 24.0 m * 3.0 m = 648.0 m³
Mass = 1000 kg/m³ * 648.0 m³ = 648000 kg
Now, let's calculate the force:
Force = Mass * Acceleration due to gravity
The acceleration due to gravity is approximately 9.8 m/s²:
Force = 648000 kg * 9.8 m/s² = 6350400 N
Finally, let's calculate the pressure on the bottom of the pool by dividing the force by the area of the pool:
Pressure = Force / Area
The area is given by the width multiplied by the length:
Area = Width * Length
Plugging in the given values:
Area = 9.0 m * 24.0 m = 216.0 m²
Pressure = 6350400 N / 216.0 m² = 29420 N/m² or 29.42 kPa
Therefore, the pressure on the bottom of the pool due to the water is approximately 29.42 kilopascals.
force 1215 m
what is that about?
Anyway
all that matters is depth
p = rho g h
= 1000 kg/m^3 * 9.81 * 3
= about 30,000 Pascals
that is the pressure abouve the one atmosphere at the surface or "gage" pressure.
That one atmosphere is about 100,000 Pascals
so the total absolute pressure is about
130,000 Pascals
a Pascal is a newton per m^2