What is the pressure at a depth of 80 m in the ocean? The density of seawater is 1. 03 × 10 3kg/m3. Please express your answer in units of atm.
To calculate the pressure at a certain depth in the ocean, we can use the formula:
Pressure = Density * Gravity * Depth
First, let's convert the given density of seawater from kg/m^3 to g/cm^3:
1.03 × 10^3 kg/m^3 = 1.03 × 10^3 g/m^3 = 1.03 g/cm^3
Next, we need to convert the depth from meters to centimeters since the density is now in g/cm^3:
80 m = 80 * 100 cm = 8000 cm
Now, we can plug in the values into the formula:
Pressure = 1.03 g/cm^3 * 9.8 m/s^2 * 8000 cm
Before calculating, we need to make sure the units are consistent. 1 atm is defined as 1.01325 × 10^6 g/cm^2. So, we can divide our final value by this conversion factor:
Pressure = (1.03 g/cm^3 * 9.8 m/s^2 * 8000 cm) / (1.01325 × 10^6 g/cm^2)
By simplifying the equation, we find:
Pressure = 79.826 atm
Therefore, the pressure at a depth of 80 m in the ocean is approximately 79.826 atm.