A net force of 20N acts on a 5kg object.Determine how far the object travels starting from rest to acquire a speed of 8m/s
F = ma, so a = 4 m/s^2
v = at, so 8 = 4t. t=2 s
s = 1/2 at^2 = 2*4 = 8 m
To determine how far the object travels, we can use the equations of motion. Specifically, we can use the equation that relates force, mass, acceleration, and displacement:
F = m * a
Here, F is the net force, m is the mass of the object, a is the acceleration of the object, and displacement is the distance traveled.
First, we need to find the acceleration of the object using the net force and the mass:
F = m * a
20N = 5kg * a
Rearranging the equation, we find:
a = 20N / 5kg
a = 4 m/s^2
Now that we have the acceleration, we can use another equation of motion to find the displacement:
v^2 = u^2 + 2a * s
Here, v is the final velocity of the object, u is the initial velocity (which is 0 since it starts from rest), a is the acceleration, and s is the displacement.
Rearranging the equation, we find:
s = (v^2 - u^2) / (2a)
s = (8m/s)^2 - (0m/s)^2 / (2 * 4m/s^2)
s = 64m^2/s^2 / 8m/s^2
s = 8m
Therefore, the object travels a distance of 8 meters starting from rest to acquire a speed of 8 m/s.