The water level in a spherical bowl has a diameter of 30cm. If the horizontal diameter of the bowl is 10cm below the water level. calculate the radius of the bowl and the depth of the water in the bowl.
Let the radius be r
R^2=5^2+15^2
R =√250
R =15.8
Depth of water = 5 + 15.8
= 20.8
sketch a cross-section, and complete the right-angled triangle
let the radius be r
r^2 = 10^2 + 15^2
r = √325
depth of water = 10 + √325
= ...
18.303
I want to see how the diagram we look out on this question. Please reply it.
The water level in a spherical bowl has a diameter of 30cm. If the horizontal diameter of the bowl is 10cm below the water level. calculate the radius of the bowl and the depth of the water in the bowl.