Let a be -1/6 and let b be 1/2. Let x be the sum of the reciprocals of a and b, let y be the product of the reciprocals of a and b, and let z be twice the reciprocal of a divided by the reciprocal of b. Calculate x+y+z.
the answer is -22
I just did the problem
Well, let's start by finding the reciprocals of a and b. The reciprocal of a is -6 (because -1/6 * -6 = 1) and the reciprocal of b is 2 (because 1/2 * 2 = 1).
Now, let's find the sum of the reciprocals of a and b: x = -6 + 2 = -4.
Next, let's find the product of the reciprocals of a and b: y = -6 * 2 = -12.
Finally, let's find twice the reciprocal of a divided by the reciprocal of b: z = 2 * (-6 / 2) = -6.
Now, if we add x, y, and z together, we get: x + y + z = -4 + (-12) + (-6) = -22.
So, x + y + z equals -22. But don't worry, it's just a number, not a reflection of your intelligence!
To calculate x, we need to find the sum of the reciprocals of a and b. So, let's find the reciprocal of a and b first.
The reciprocal of a is the number that, when multiplied by a, gives the product 1. In this case, a = -1/6, so the reciprocal of a is -6/1 or -6.
The reciprocal of b is the number that, when multiplied by b, gives the product 1. In this case, b = 1/2, so the reciprocal of b is 2/1 or 2.
Now, let's calculate x:
x = reciprocal of a + reciprocal of b
= -6 + 2
= -4
Next, we need to calculate y, which is the product of the reciprocals of a and b:
y = reciprocal of a * reciprocal of b
= -6 * 2
= -12
Finally, we need to calculate z, which is twice the reciprocal of a divided by the reciprocal of b:
z = 2 * (reciprocal of a) / (reciprocal of b)
= 2 * (-6) / 2
= -6
Now, let's find x+y+z:
x + y + z = (-4) + (-12) + (-6)
= -22
Therefore, x+y+z equals -22.
reciprocal of -1/6
=6
and that of 1/2=2
a=-6
b=2
a+b=x
-6+2=x
x=-4
y=a*b
y=-6*2
y=-12
z=2(a)/b
z=2*-6/2
z=-6
now x+y+z=??