a person, with his ears to the ground, seconds a huge stone strike the concrete pavement. a moment later two sounds are heard from the impact, one travels in the air and other in the concrete, and they are 0.80 seconds apart. How far away the impact occur?
I do not understand "seconds a huge stone"
Me either but you'll have to compare the speed of sound to the speed of sound in concrete.
To determine the distance at which the impact occurred, we need to use the speed of sound in air and in concrete.
First, let's calculate the distance traveled by the sound traveling through the air. The speed of sound in air is approximately 343 meters per second. Since the sound took 0.80 seconds to reach the person's ears through the air, we can multiply the speed of sound by the time it took:
Distance through air = Speed of sound in air × Time taken
Distance through air = 343 m/s × 0.80 s
Distance through air = 274.4 meters
Next, let's calculate the distance traveled by the sound traveling through the concrete. The speed of sound in concrete is faster than in air; typically around 3430 meters per second. Since the sound arrival occurred 0.80 seconds after the air arrival, we can calculate the distance traveled through the concrete similarly:
Distance through concrete = Speed of sound in concrete × Time taken
Distance through concrete = 3430 m/s × 0.80 s
Distance through concrete = 2744 meters
Therefore, the impact occurred at a distance of 2744 meters away from the person.