A chemist needs a 50% of sulfuric acid. She mix 2 liters of 20% of sulfuric acid with a sample of 60% of sulfuric acid. Write a equatoin that models the situation and use it to find how much the 50% of the sulfuric acid she needs to use?
Ok, she has figured out how to make 50 percent solution, and the above
Ok, how much 60Percent she needs?
2liters*.2 + V*.6=(V+2).5
solve for V
.4+.6V=.5V+1
.1V=.6
V=6 liters
check my math.
To solve this problem, let's set up an equation based on the given information.
Let "x" represent the amount (in liters) of the 50% sulfuric acid the chemist needs to use.
We are told that the chemist has 2 liters of 20% sulfuric acid. This means that out of the 2 liters, 20% is sulfuric acid. So, the amount of sulfuric acid in those 2 liters is: 2 liters * 20% = 0.2 liters.
The chemist also has a sample of 60% sulfuric acid, and we don't know the volume of this sample, so let's call it "y" liters. Therefore, the amount of sulfuric acid in this sample is: y liters * 60% = 0.6y liters.
Now, let's set up the equation based on the mixture of the two sulfuric acid solutions:
Amount of sulfuric acid in the 20% solution + Amount of sulfuric acid in the 60% solution = Amount of sulfuric acid in the 50% solution
0.2 liters + 0.6y liters = 0.5x liters
Simplifying the equation, we have:
0.2 + 0.6y = 0.5x
Now we can solve for x, the amount of 50% sulfuric acid the chemist needs to use.
Please note that we are missing one important piece of information in order to solve for x fully, which is the value of y (the volume of the 60% sulfuric acid sample). Without knowing this value, we won't be able to determine the exact amount of 50% sulfuric acid required.