do you mean like this:
720/(V-30) + 720/(V+30) = 10
Get a common denominator of
(v-30)(v+30)
then multiplying both sides by that, then
(v-30)(v+30)X 720(V+30) + (v-30)(v+30) X 720(V-30)=(v-30)(v+30)X 10(v-30)(v+30)
then multily out, and solve for v.
720(v-30)+720(v+30)=10
720v-21600+720v+21600=10
1440v=10
v=144
The right side: you have to multipy both sides by (v-30)(v+30
720(v-30)+720(v+30)=10(v-30)(v+30)
You will get a quadratic.
As an aside, 1440v if it equalled 10, does not give v=144. It gives 1/144.
Yes, that's correct! It seems like you're solving an equation using algebraic manipulation. Let me explain the steps in a bit more detail:
1. Start with the equation: 720/(V-30) + 720/(V+30) = 10.
2. Get a common denominator of (V-30)(V+30) for both fractions on the left side. Multiply the first fraction by (V+30)/(V+30) and the second fraction by (V-30)/(V-30):
(720(V+30) + 720(V-30))/((V-30)(V+30)) = 10.
3. Multiply both sides of the equation by (V-30)(V+30) to eliminate the denominators:
720(V+30) + 720(V-30) = 10(V-30)(V+30).
4. Simplify and expand both sides of the equation:
720V + 21600 + 720V - 21600 = 10(V^2 - 900).
This simplifies to: 1440V = 10V^2 - 9000.
5. Rewrite the equation in quadratic form, by moving all terms to one side:
10V^2 - 1440V - 9000 = 0.
6. Solve the quadratic equation using factoring, completing the square, or the quadratic formula. In this case, it looks like factoring may work:
10V^2 - 1440V - 9000 = (V - 144)(10V + 63) = 0.
Setting each factor equal to zero, we have V - 144 = 0 or 10V + 63 = 0.
This gives two possible solutions: V = 144 or V = -63/10.
So, in conclusion, the equation has two possible solutions: V = 144 or V = -63/10. Remember to always double-check your solutions by substituting them back into the original equation to ensure they satisfy the equation.