Mrs. Shelton doesn't have enough marking pens for everyone in class. Every 2 students share a green pen and every 4 students share a red pen. If she has
15 marking pens in all how many students are in Mrs. Shelton's class?
there is 20 kids min the class
To solve this problem, we can start by assigning variables to the unknown quantities. Let's call the number of students in the class "S".
According to the problem, every 2 students share a green pen. This means that the number of green pens required is equal to half the number of students in the class, or S/2.
Similarly, every 4 students share a red pen. Therefore, the number of red pens required is equal to one-fourth of the number of students in the class, or S/4.
Since Mrs. Shelton has a total of 15 marking pens, the sum of the green pens and red pens should be equal to 15:
S/2 + S/4 = 15
To solve this equation, we can multiply through by the least common denominator (4) to eliminate the fractions:
2S + S = 60
Combine like terms:
3S = 60
Divide both sides by 3 to isolate S:
S = 60/3
Simplify:
S = 20
Therefore, there are 20 students in Mrs. Shelton's class.