if 8.99g of scandium and 8.99g of oxgen react to give scandium oxide and a leftover 3.56g.what percentage of scandium oxide is the oxygen
I don't think the problem is made up to be a REAL problem.
SCxOy is the compound.
8.99 g Sc used.
8.99-3.56 = 5.43 g O used.
Total mass ScxOy = 8.99+5.43 = 14.42
%O = (5.43/14.42)*100 = ? but in REAL Sc2O3 the %O is 34.8%.
To find the percentage of oxygen in scandium oxide, we need to calculate the molar mass of scandium oxide and determine the molar mass of oxygen in it.
Step 1: Convert the given masses of scandium (Sc) and oxygen (O) to moles using the molar mass of each element.
- Molar mass of scandium (Sc) = 44.96 g/mol
- Moles of scandium (Sc) = mass of scandium (g) / molar mass of scandium (g/mol)
Moles of scandium (Sc) = 8.99 g / 44.96 g/mol
Moles of scandium (Sc) = 0.2001 mol
- Molar mass of oxygen (O) = 16.00 g/mol
- Moles of oxygen (O) = mass of oxygen (g) / molar mass of oxygen (g/mol)
Moles of oxygen (O) = 8.99 g / 16.00 g/mol
Moles of oxygen (O) = 0.5619 mol
Step 2: Determine the number of moles of oxygen in the leftover.
- Moles of leftover = 3.56 g / molar mass of oxygen (g/mol)
Moles of leftover = 3.56 g / 16.00 g/mol
Moles of leftover = 0.2225 mol
Step 3: Calculate the number of moles of oxygen in scandium oxide.
Since the ratio between scandium and oxygen in the reaction is 1:1, the moles of oxygen in scandium oxide will be equal to the moles of scandium.
Moles of oxygen in scandium oxide = Moles of scandium (Sc) = 0.2001 mol
Step 4: Calculate the percentage of oxygen in scandium oxide.
Percentage of oxygen in scandium oxide = (Moles of oxygen in scandium oxide / Total moles of scandium oxide) x 100
Percentage of oxygen in scandium oxide = (0.2001 mol / (0.2001 mol + 0.2225 mol)) x 100
Percentage of oxygen in scandium oxide ≈ 47.3%
Therefore, the percentage of oxygen in scandium oxide is approximately 47.3%.
To find the percentage of oxygen in scandium oxide, we need to determine the amount of oxygen in the leftover sample and in the scandium oxide, and then calculate the percentage.
First, we need to find the amount of oxygen in the leftover sample:
Given: Mass of leftover sample = 3.56g
Next, we need to find the amount of oxygen in the scandium oxide:
Given: Mass of scandium = 8.99g
Given: Mass of oxygen = 8.99g
Since scandium and oxygen react in a 1:1 ratio to form scandium oxide, the mass of the formed oxide is also 8.99g. Therefore, the mass of oxygen in the scandium oxide is also 8.99g.
Now, we can calculate the percentage of oxygen in scandium oxide:
Percentage of oxygen = (Mass of oxygen / Mass of scandium oxide) x 100
Substituting the known values:
Percentage of oxygen = (8.99g / 8.99g) x 100
Percentage of oxygen = 100%
Therefore, the percentage of oxygen in scandium oxide is 100%.