A total of Rs.14,000 is invested for a year, part at 5% and the rest at 6%. If Rs.740 is the total interest, amount invested at 5% is:
can you solve it ...!!!
plzzzzzzz,, I wanna solution
Let's solve this step-by-step.
Let's assume the amount invested at 5% is x.
The amount invested at 6% would be 14000 - x since the total investment is Rs. 14,000.
Now, we can calculate the interest earned on these two investments separately.
Interest earned on the investment at 5% = (x * 5%) = 0.05x
Interest earned on the investment at 6% = ((14000 - x) * 6%) = 0.06(14000 - x)
The total interest earned is given as Rs. 740.
So, the equation becomes:
0.05x + 0.06(14000 - x) = 740
Simplifying this equation, we get:
0.05x + 840 - 0.06x = 740
-0.01x = -100
Dividing both sides by -0.01, we get:
x = 10000
Therefore, the amount invested at 5% is Rs. 10,000.
To find the amount invested at 5%, we need to set up an equation based on the information given.
Let's assume that the amount invested at 5% is x.
The amount invested at 6% would be (14000 - x) since the total amount invested is Rs.14,000.
Next, we'll calculate the interest earned on each amount and add them together to get the total interest earned.
Interest earned on the amount invested at 5% = x * 5% = (0.05x)
Interest earned on the amount invested at 6% = (14000 - x) * 6% = (0.06(14000 - x))
The total interest earned is given as Rs.740, so we can set up the equation:
0.05x + 0.06(14000 - x) = 740
Simplifying the equation:
0.05x + 0.06 * 14000 - 0.06x = 740
0.05x + 840 - 0.06x = 740
-0.01x = 740 - 840
-0.01x = -100
x = (-100) / (-0.01)
x = 10000
Therefore, the amount invested at 5% is Rs.10,000.