A gaseous mixture of O2 and N2 contains 31.8 % nitrogen by mass. What is the partial pressure of oxygen in the mixture if the total pressure is 445 mmHg?
The partial pressure of the gasses reflects the mole ratios of the gasses.
http://en.wikipedia.org/wiki/Partial_pressure
Assume 100grams of gas. 31.8 grams is N2, or the moles of N2 is 31.8/28=1.14
The moles of O2 will be 68.2/32=2.15
pressureN2/PressureO2 =
X/(445-x)=1.14/2.15
2.15x=1.14(445-x)
3.29x=507
pressureN2=154
pressureO2=291mmHg
check my work.
your answer was correct!
it looks complicated, but substitute your own numbers and follow his math process and it all works out for correct answer.
my P=825mmHg and 36.8% N2 was worked correctly.
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I feel the chemistry between us ;)
Don't worry, I'm already measuring the noose...