Find molarity of alcl3 if normality is 0.2
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To find the molarity of a solution from its normality, you need to know the number of equivalents of the solute in a given volume of the solution. Now, let's proceed step by step to solve the problem:
Step 1: Understand the Relationship between Normality and Molarity
Normality (N) is a measure of the concentration of a solution based on its chemical equivalence. Normality is equal to the number of equivalents per liter of solution.
Molarity (M) is a measure of the concentration of a solution based on the amount of solute (in moles) per liter of solution.
For a compound like AlCl3, it can be dissociated into one Al3+ ion and three Cl- ions:
AlCl3 → Al3+ + 3Cl-
Since AlCl3 dissociates into one Al3+ ion, the equivalent weight of AlCl3 is equal to its molar mass.
Step 2: Calculate the Equivalent Weight
The molar mass of AlCl3 can be calculated using the atomic masses of aluminum (Al) and chlorine (Cl):
Molar mass of AlCl3 = (1 × Atomic mass of Al) + (3 × Atomic mass of Cl)
Atomic mass of Al = 26.98 g/mol
Atomic mass of Cl = 35.45 g/mol
Molar mass of AlCl3 = (1 × 26.98 g/mol) + (3 × 35.45 g/mol)
Step 3: Calculate the Molar Mass of AlCl3
Molar mass of AlCl3 = 133.33 g/mol
Step 4: Find the Molarity from Normality
The molarity (M) can be calculated using the following formula:
Molarity (M) = Normality (N) / Equivalent Weight
Substituting the given values into the formula:
Molarity of AlCl3 = 0.2 N / 133.33 g/mol
Carrying out the calculation gives you the molarity of AlCl3.
What subject is dav?
Don't I need the density of the solution?