so I tried to expand this question and I got
x^3 *x2, i don't know if it's right but if not can I get a step by step explanation please,
Expand
(2x + y^2)^5.
(Simplify your answer completely.)
look up binomial expansion
(p+q)^n = p^n + C(n,1) p^(n-1)q^1 ... etc
where
c(n,m) = n!/[(n-m)! m!]
for n = 5
the coefs are
1 5 10 10 5 1
so
32x^5 + 5*16x^4*y^2 ...... y^10