If I were to graph it, the vertex would be (3,-7) so what would my other point be?
Write this equation :
y =4(x-3)^2 -7 in standard form .
answer: y=4x^2 -24x +29
idk if this is right?
other point? chose an easy x, such as x=0, compute y (y=29), and immediately you can use symettry for x=6, y=29
so is the answer I put correct in standard form??
To find the second point on the graph, we can use the fact that the vertex of a parabola is the lowest or highest point on the graph. The vertex form of a quadratic equation is given by y = a(x - h)^2 + k, where the vertex is located at the point (h, k).
In this case, the given vertex is (3, -7), which means that the equation can be rewritten as y = 4(x - 3)^2 - 7.
Now, to convert it into standard form, you need to expand the equation.
Start by applying the distributive property to (x - 3)^2:
y = 4(x^2 - 6x + 9) - 7
Next, distribute the 4 to each term inside the parentheses:
y = 4x^2 - 24x + 36 - 7
Combine like terms:
y = 4x^2 - 24x + 29
So, the equation in standard form is y = 4x^2 - 24x + 29. Therefore, the answer you provided is correct.