A sample of co2 occupies 6.00l at 25c and 700. MmHg. What is the volume of the gas at stp
(P1V1/T1) = (P2V2/T2)
wright college
To find the volume of the gas at STP (Standard Temperature and Pressure), we need to use the ideal gas law equation, which is:
PV = nRT
Where:
P = pressure (in atm)
V = volume (in liters)
n = number of moles
R = ideal gas constant (0.0821 L·atm/mol·K)
T = temperature (in Kelvin)
We need to convert the temperature from Celsius to Kelvin:
T(K) = T(°C) + 273.15
T(K) = 25°C + 273.15
T(K) = 298.15 K
Now, let's calculate the number of moles (n) using the ideal gas law equation:
n = PV / RT
Plugging in the values:
P = 700 mmHg = 700/760 atm (using the conversion 1 atm = 760 mmHg)
V = 6.00 L
T = 298.15 K
R = 0.0821 L·atm/mol·K
n = (700/760) * 6.00 / (0.0821 * 298.15)
Now, let's solve for n:
n = 0.619 mol
We have found the number of moles, n. Now we can use this value to find the volume at STP.
At STP, the pressure is 1 atm and the temperature is 273.15 K. We can use the same ideal gas law equation to find the volume at STP (V2):
V2 = nRT2 / P2
Plugging in the values:
n = 0.619 mol
R = 0.0821 L·atm/mol·K
T2 = 273.15 K
P2 = 1 atm
V2 = 0.619 * 0.0821 * 273.15 / 1
Now, let's solve for V2:
V2 = 13.04 L
Therefore, the volume of the gas at STP is 13.04 liters.
To find the volume of the gas at STP (Standard Temperature and Pressure), we need to use the ideal gas law equation. The ideal gas law equation is:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin.
Given:
P = 700 mmHg
V = 6.00 L
T = 25°C (298 K)
First, we need to convert the pressure from mmHg to atmospheres (atm) since the ideal gas constant is commonly expressed using atm as the unit. There are 760 mmHg in 1 atm, so we divide 700 mmHg by 760 to get:
P = 700 mmHg / 760 mmHg/atm ≈ 0.921 atm
Next, we can rearrange the ideal gas law equation to solve for the unknown volume at STP:
V₁ / T₁ = V₂ / T₂
where V₁ is the initial volume, T₁ is the initial temperature, V₂ is the final volume (at STP), and T₂ is the final temperature (at STP).
At STP, the standard temperature is 273 K.
Solving for V₂:
V₂ = (V₁ * T₂) / T₁
Using the values we know:
V₂ = (6.00 L * 273 K) / 298 K ≈ 5.49 L
Therefore, the volume of the gas at STP is approximately 5.49 liters.