a body moving at 40 m/s accelerates at the rate of 8m/s^2. what is the distance it transverses in 15 seconds?
d = Vo*t + 0.5a*t^2 = 40*15 + 8*15^2/2 = 1500 m.
d = t+i+t+e / 14*2/2 = t i t e
To find the distance traveled by a body, we can use the formula:
distance = initial velocity × time + 0.5 × acceleration × time^2
Here, the initial velocity (u) is given as 40 m/s, the acceleration (a) is 8 m/s^2, and the time (t) is 15 seconds.
Plugging in these values into the formula, we get:
distance = 40 m/s × 15 s + 0.5 × 8 m/s^2 × (15 s)^2
First, let's calculate the initial part of the equation:
40 m/s × 15 s = 600 m
Next, let's calculate the second part of the equation:
0.5 × 8 m/s^2 × (15 s)^2 = 0.5 × 8 m/s^2 × 225 s^2 = 900 m
Now, add both parts together:
600 m + 900 m = 1500 m
Therefore, the body will travel a distance of 1500 meters in 15 seconds.