How would i solve 3x^2 - 4 = 0?
And in simplest radical form?
x^2 = 4/3
x = + 2/sqrt 3 = (2/3)sqrt
or
x = - 2/sqrt 3 = -(2/3) sqrt 3
That dosen`t solve the whole question though =(.
To solve the equation 3x^2 - 4 = 0, you need to find the value(s) of x that make the equation true.
Step 1: Set the equation equal to zero:
3x^2 - 4 = 0
Step 2: Add 4 to both sides of the equation to isolate the x terms:
3x^2 = 4
Step 3: Divide both sides of the equation by 3 to solve for x^2:
x^2 = 4/3
Step 4: Take the square root of both sides of the equation to solve for x:
x = ±√(4/3)
Step 5: Simplify the radical:
x = ±√(4)/√(3)
= ±(2/√(3))
So, the solutions to the equation 3x^2 - 4 = 0 are x = 2/√(3) and x = -2/√(3).