A boy is flying a kite on a string 33m long. The string which is being held at 1.5m above the ground, makes an angle of 39* with the horizontal. How high is the kite above the ground (nearest cm)
Dk=33sin39+1.5 Dk=20.8+1.5=22.3m
To find the height of the kite above the ground, we can use trigonometry.
If we draw a diagram, we can see that the string of the kite forms a right triangle with the ground. The length of the string forms the hypotenuse of the triangle, and the height of the kite forms the opposite side.
Given:
- Length of the string (hypotenuse) = 33m
- Angle between the string and the ground = 39°
We can use the sine function to find the height of the kite above the ground:
sin(angle) = opposite / hypotenuse
Plugging in the values we know:
sin(39°) = opposite / 33m
Now, let's solve for the opposite (height of the kite).
opposite = sin(39°) * 33m
Using a calculator, we can find that sin(39°) is approximately 0.6293.
opposite ≈ 0.6293 * 33m
opposite ≈ 20.73m
Therefore, the height of the kite above the ground is approximately 20.73 meters.
Converting this height to centimeters, multiply by 100 to get:
20.73m * 100 = 2073cm
So, the height of the kite above the ground (nearest cm) is approximately 2073cm.