A car accelerates uniformly from rest at 3m/s(square).What is its velocity after travelling a distance of 24m?
a = 3 m/s^2
Vi = 0
d = 24 m
d = (1/2) a t^2
24 = (1/2)(3)t^2
t^2 = 48/3 = 16
t = 4 seconds
v = Vi + a t
v = 0 + 3 (4)
v = 12 m/s
U_3ms-1
-a=24m
t=?
V=0
V=u+at
O=3+(-24t)
0_3=-24t
-3\1=-24t/1 =8s
To find the velocity of the car after traveling a distance of 24m, we can use the equation:
v² = u² + 2as
Here,
v = final velocity
u = initial velocity (0 m/s as the car starts from rest)
a = acceleration (given as 3 m/s²)
s = distance traveled (given as 24m)
Since the car starts from rest, the initial velocity (u) is 0 m/s. Plugging in the given values, we get:
v² = 0² + 2 * 3 * 24
Simplifying the equation:
v² = 0 + 72
v² = 72
Taking the square root of both sides:
v = √72
v ≈ 8.49 m/s
Therefore, the velocity of the car after traveling a distance of 24m is approximately 8.49 m/s.
To find the velocity of a car that is accelerating uniformly, we can use the kinematic equation:
v^2 = u^2 + 2as
Where:
v = final velocity
u = initial velocity (which is 0 since the car starts from rest)
a = acceleration
s = distance traveled
In this case, we know that the initial velocity (u) is 0 m/s, the acceleration (a) is 3 m/s², and the distance traveled (s) is 24 m.
Plugging these values into the equation, we get:
v^2 = 0^2 + 2 * 3 * 24
Simplifying:
v^2 = 0 + 72
v^2 = 72
To find the velocity (v), we need to take the square root of both sides of the equation:
v = √72
Calculating the square root of 72, we find:
v ≈ 8.49 m/s
So, the velocity of the car after traveling a distance of 24 m is approximately 8.49 m/s.