A windowpane is half a centimeter thick and has an area of 1.0 m2. The temperature difference between the inside and outside surfaces of the pane is 15° C. What is the rate of heat flow through this window? (Thermal conductivity for glass is 0.84 J/s×m×°C.)
thickness = .005 meter
Q =0.84 * Area * (delta T) /thickness
= 0.84 * 1 * 15 /.005 Joules/second which is Watts by the way
To calculate the rate of heat flow through the window, we can use the formula:
Q = (k * A * ΔT) / d
Where:
Q = rate of heat flow (in J/s)
k = thermal conductivity of the material (in J/s*m*°C)
A = area of the window (in m^2)
ΔT = temperature difference between the inside and outside surfaces (in °C)
d = thickness of the windowpane (in meters)
Given values:
k = 0.84 J/s*m*°C
A = 1.0 m^2
ΔT = 15 °C
d = 0.5 cm = 0.005 m
Substituting these values into the formula, we have:
Q = (0.84 * 1.0 * 15) / 0.005
Now we can calculate the rate of heat flow through the window:
Q = 252 J/s
Therefore, the rate of heat flow through this window is 252 J/s.
To calculate the rate of heat flow through the window, we can use the formula for heat flow:
Q = (k * A * ΔT) / d
where:
Q = rate of heat flow
k = thermal conductivity
A = area of the window
ΔT = temperature difference
d = thickness of the windowpane
Let's plug the given values into the formula:
k = 0.84 J/s×m×°C (given)
A = 1.0 m^2 (given)
ΔT = 15°C (given)
d = 0.5 cm = 0.005 m (half a centimeter is 0.005 meters)
Substituting these values into the formula, we get:
Q = (0.84 * 1.0 * 15) / 0.005
Simplifying the expression:
Q = 12.6 / 0.005
Q = 2520 J/s
Therefore, the rate of heat flow through this window is 2520 J/s.