If the equation of a circle is (x + 5)2 + (y - 7)2 = 36, its center point is
Dear Kyle,
the equation of circle
let (h,k) be the center of the circle
let the radius be r
then the equation of circle will be
(x-h)^2 + (y-k)^2 = r^2
so according to your equation of circle given
the center point= (-5,7)
To find the center point of a circle given its equation, we look at the equation in the form (x - h)² + (y - k)² = r², where (h, k) represents the coordinates of the center point and r represents the radius.
In this case, we have the equation (x + 5)² + (y - 7)² = 36. Comparing this equation to the general form, we can determine that the center point has coordinates (-5, 7).
Therefore, the center point of the circle is (-5, 7).
To find the center point of a circle given its equation, we need to identify the coordinates (h, k) in the equation of the circle in standard form: (x - h)² + (y - k)² = r².
In the given equation, (x + 5)² + (y - 7)² = 36, we can see that the values of (h, k) are (-5, 7). Therefore, the center point of the circle is (-5, 7).