How do you solve the equation log(x+6)-log(2x+1)=log4
loga-logb=log(a/b)
log((x+6)/(2x+1))=log4
take the antilog of each side
(x+6)/(2x+1)=4
solve that.
log((x+6)/(2x+1))=log4
take the antilog of each side
(x+6)/(2x+1)=4
solve that.