You take a trip by air that involves three independent flights. If there is an 67% chance each specific leg of the trip is on time, what is the probability all three flights arrive on time? (Round your answer to 3 decimal places.)

Probability=

To find the probability that all three flights arrive on time, we can multiply the individual probabilities of each leg being on time.

Given that there is a 67% chance each specific leg of the trip is on time, the probability of each leg being on time is 0.67.

To find the probability of all three flights being on time, we multiply these probabilities together:

Probability = 0.67 * 0.67 * 0.67

Calculating this, we get:

Probability = 0.67^3 ≈ 0.300

Therefore, the probability that all three flights arrive on time is approximately 0.300, rounded to 3 decimal places.

P(all) = 3C3 (.67)^3 (.33)^0 =

.099