A photo lab manager graphed the cost of having photos developed as a function of the number of photos in the order. The graph is a line with a slope of 1/10 that passes through (10,6). Write an equation in slope-intercept form that describes the cost to have photos developed. How much does it cost to have 25 photos developed?
I will assume that your given ordered pair (10,6) is of the type (number , cost), then
cost - 6 = (1/10)(number -10)
cost = (1/10) number -1 + 6
cost = (1/10)n + 5
so if n = 25
cost = (1/10)(25) + 5 = 7.5 units of cost (you gave no units)
So if slope intercept form is y=mx+b what would this equation look like for this word problem?
Thanks
I gave it to you ...
instead of y I have "cost"
instead of x I have "n"
y = mx + b <-----> cost = (1/10)n + 5
It should be y=10x+5
it would cost $7.50
To write an equation in slope-intercept form, we need to use the slope-intercept form equation, which is y = mx + b, where m is the slope and b is the y-intercept.
In the given problem, it's mentioned that the graph is a line with a slope of 1/10 that passes through the point (10,6). So, we have:
m = 1/10 (slope)
(x1, y1) = (10, 6) (point)
We can substitute the values into the equation and solve for b:
6 = (1/10)(10) + b
6 = 1 + b
b = 6 - 1
b = 5
Therefore, the equation for the cost to have photos developed is:
y = (1/10)x + 5
To find the cost of having 25 photos developed, we can substitute x = 25 into the equation and solve for y:
y = (1/10)(25) + 5
y = 2.5 + 5
y = 7.5
So, it will cost $7.50 to have 25 photos developed.