slove for ^x

x^2-3x-18=0

(x-6)(x+3)

To solve the equation x^2 - 3x - 18 = 0 for x, we can use the quadratic formula. The quadratic formula states that for an equation in the form ax^2 + bx + c = 0, the solutions for x can be found using the formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

For the given equation x^2 - 3x - 18 = 0, we have a = 1, b = -3, and c = -18. Plugging these values into the quadratic formula, we get:

x = (-(-3) ± √((-3)^2 - 4(1)(-18))) / (2(1))

Simplifying further:

x = (3 ± √(9 + 72)) / 2

x = (3 ± √81) / 2

Since √81 = 9, we can simplify the equation to:

x = (3 ± 9) / 2

This gives us the two possible solutions:

x1 = (3 + 9) / 2 = 12 / 2 = 6
x2 = (3 - 9) / 2 = -6 / 2 = -3

Therefore, the solutions to the equation x^2 - 3x - 18 = 0 are x = 6 and x = -3.