3PbO2 + 2Cr3++ 2H2O3Pb2+ + 2CrO42-+ 4H+
In the above redox reaction, use oxidation numbers to identify the element oxidized, the element reduced, the oxidizing agent and the reducing agent.
1.name of the element oxidized:
2.name of the element reduced:
3.formula of the oxidizing agent:
4.formula of the reducing agent:
Oxidation is the loss of electrons
Reduction is the gain of electrons.
The substance oxidized is the reducing agent.
The substance reduced is the oxidizing agent.
Here are some hints:
Pb is +4 on the left and +2 on the right.
Cr is +3 on the left and +6 on the right.
I really don't have a clue
You won't get a clue, either, unless you try. I assume you are just trying to get answers and you're not trying to understand how to do them. Most of us volunteers on this board will go way out of our way to help but help is what we give, not freebie answer all day long.
chemistry is my weak subject hence why i am on here to get help.
I have online questions that need answering in a day and im stuck that's the truth.
I have to fnd someone that I might have to pay then looks like it... :(
I suggest that if you are this lost that you get a tutor. Don't wait.
can you not help me?
To identify the element oxidized, reduced, oxidizing agent, and reducing agent in the given redox reaction, you need to assign oxidation numbers to each element and compare them before and after the reaction.
1. The element that is oxidized is the one that experiences an increase in its oxidation number. In this reaction, the oxidation number of Cr increases from +3 to +6. Therefore, the element oxidized is chromium (Cr).
2. The element that is reduced is the one that experiences a decrease in its oxidation number. In this reaction, the oxidation number of Pb decreases from +4 to +2. Therefore, the element reduced is lead (Pb).
3. The oxidizing agent is the species that causes another element to undergo oxidation. It itself gets reduced in the process. In this reaction, PbO2 is the oxidizing agent as it causes the oxidation of chromium. So, the formula of the oxidizing agent is PbO2.
4. The reducing agent is the species that causes another element to undergo reduction. It itself gets oxidized in the process. In this reaction, Cr3+ is the reducing agent as it causes the reduction of lead. So, the formula of the reducing agent is Cr3+.
To summarize:
1. Element oxidized: Chromium (Cr)
2. Element reduced: Lead (Pb)
3. Formula of oxidizing agent: PbO2
4. Formula of reducing agent: Cr3+