Which line has a slope of 3 and passes though the point (-6, -4)?
( y - (-4) ) / ( x -(-6) ) = 3
y+4 = 3(x+6)
y = -4 + 3 x + 18
y = 3 x + 14
The line
y+4 = 3(x+6)
does
expand and simplify it if you have to
-+- is+ so -6-4 is +10
To find the equation of a line that has a slope of 3 and passes through the point (-6, -4), we can use the point-slope form of a linear equation.
The point-slope form of a linear equation is given by:
y - y1 = m(x - x1)
Where:
- (x1, y1) is a point on the line
- m is the slope of the line
In our case, the slope (m) is 3 and the point on the line is (-6, -4). Plugging in these values into the point-slope form, we have:
y - (-4) = 3(x - (-6))
Simplifying the equation:
y + 4 = 3(x + 6)
Expanding the brackets:
y + 4 = 3x + 18
Now, we need to isolate the y variable:
y = 3x + 18 - 4
y = 3x + 14
Therefore, the equation of the line with a slope of 3 and passing through the point (-6, -4) is y = 3x + 14.