A box a weight of 100 N rests on a horizontal floor.The coefficient of static friction is 0,40 and the coefficient of kinetic friction is 0,30.DETERMISE THE FRICTIONAL FORCE ACTING ON THE BOX IF A HORIZONTAL FORCE IS APPLIED WITH A MAGNITUDE OF 0 N
Well, 0 Newtons gives 0 frictional force
If a horizontal force is applied with a magnitude of 0 N, the box will remain at rest, and the frictional force acting on the box will be the static frictional force.
The formula for the static frictional force is given as:
Fs ≤ μs * N
Where:
Fs is the static frictional force
μs is the coefficient of static friction
N is the normal force acting on the box
In this case, the weight of the box, 100 N, is equal to the normal force (N) because the box is resting on a horizontal floor. Therefore:
Fs ≤ μs * 100 N
Substituting the coefficient of static friction (μs = 0.40) into the equation:
Fs ≤ 0.40 * 100 N
Fs ≤ 40 N
Therefore, the maximum static frictional force that can act on the box is 40 N. Since a horizontal force of 0 N is applied, the frictional force acting on the box will be 0 N.
To determine the frictional force acting on the box when a horizontal force of 0 N is applied, we need to consider the coefficients of static and kinetic friction.
In this case, the applied horizontal force is 0 N, which means the box is not being pushed or pulled. As a result, the box will not experience any motion.
When the box is at rest and there is no external force acting on it (in this case, the applied force is 0 N), the frictional force opposing the impending motion is called static friction.
The static frictional force can be calculated using the formula:
Frictional force (static) = coefficient of static friction * Normal force
The normal force is the force exerted by the surface on the box, which is equal to the weight of the box (since it rests on a horizontal floor).
Given that the weight of the box is 100 N, we can now calculate the static frictional force:
Frictional force (static) = 0.40 * 100 N
Frictional force (static) = 40 N
Therefore, when a horizontal force of 0 N is applied, the static frictional force acting on the box is 40 N.