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April 23, 2014

April 23, 2014

**Recent Homework Questions About Trigonometry**

Post a New Question | Current Questions

**trig**

Determine whether the vectors are parallel, perpendicular or neither. 1) v = (4,1), w = (1,-4) 2) v = (2,3), w = (4,6) 3) v = (2,3), w = (3,-3) Please and thanks!
*Monday, April 30, 2012 at 9:15pm*

**trig**

Find the component form for vector v with the given amplitude and direction angle theta. |v|=20.6, theta=102.5deg
*Monday, April 30, 2012 at 8:51pm*

**trig**

tan = -10 sqrt2/ -10 sqrt 2 becomes tan=1 which is 45degree
*Monday, April 30, 2012 at 8:20pm*

**trig**

(-10√2, -10√2), find te magnitude and direction angle of the vector, measure the direction angle in [0, 360). Please help!
*Monday, April 30, 2012 at 8:16pm*

**trig**

What is 3*11+7*(-5) ?
*Monday, April 30, 2012 at 6:53pm*

**trig**

Find the dot product of u and v u= 3i+7j v= 11i-5j
*Monday, April 30, 2012 at 6:42pm*

**trig problem**

F = 1c/min = 1rev/min. = Frquency. P = 1/F = 1min/rev. = The period. T = 13:12:40 - 13:0:0 = 12min,40s. = 12 2/3 min. = 38/3 min. 1rev/min * (38/3)min = 12 2/3 rev. (2/3)rev * 360Deg/rev = 240 Deg. Ar=240-180 = 60 Deg.=Reference angle. h = hmax*sinAr = 6*sin60 = 5.2 m.
*Monday, April 30, 2012 at 3:05pm*

**Application prob. for Trig.**

Hi, A fountain in a shopping centre has a single jet of water. The height of the jet of water varies according to a sinusoidal function. A student notes that, in exactly one minute, the jet goes from a minimum height of 2m to a maximum height of 6m and back to 2m. At 13:00, ...
*Monday, April 30, 2012 at 1:19pm*

**trig**

since it's a max at t=0, that indicates a cosine function The period is 1, so we are looking at cos(2pi*t) max is 120, min is 80, so amplitude is 20, and oscillates around h=100, and our function is f(t) = 100 + 20cos(2pi*t)
*Monday, April 30, 2012 at 11:54am*

**trig**

At rest, the human heart beats once every second. At the strongest part of the beat, a person's blood pressure peaks at 120mmHg. At the most relaxed part of the beat, a person's blood pressure drops to 80mmHg. Supposing that t = 0 corresponds to the peak of the beat, ...
*Monday, April 30, 2012 at 4:05am*

**Pre-Calc/Math**

1) rewrite cosx (cosx/sinx) + sinx = csc x 2) cosx^2/sinx + sinx = csc x 3) multiply sinx by (sinx/sinx) to get same denominator this gives you cosx^2/sinx + sinx^2/sinx = cscx 4) combine your fractions (cosx^2 + sinx^2)/sinx = cscx 5) rewrite numerator 1/sinx= csc x and there...
*Monday, April 30, 2012 at 1:00am*

**trig - incomplete**

"near" doesn't mean anything. If the man is 100 ft from the tree, a 4-ft shadow means the tree is enormous. If the man is 2 ft from the tree, the tree is short.
*Monday, April 30, 2012 at 12:18am*

**trig**

a 6 foot tall man is standing near a tree on level ground .if the man shadow 4 feet long .how many feet tall is the tree?
*Sunday, April 29, 2012 at 11:08pm*

**Trig. application**

C = pi * D = 3.14 * 2*25.5 = 160.14 cm. = 1.614 m = Circumference. V = 30km/h = 30,000m / 60min=500 m/min. d = 500m/min * 4min = 2000 m. 2000m / 1.614m/rev =1239.157373 revolutions. A = 90 + 0.157373*90 = 104.2 Deg. h = 25.5 + 25.5*sin104.2 = 50.2 cm.
*Sunday, April 29, 2012 at 10:29pm*

**Honors Trig.**

Here is an easy way to do these. 1) convert all angles to 000N,090E, 180S, 270W Example: 456@29deg S of E. = 456@119 then convert to N, E coordinates. V= 456(Cos119 N + Sin119 E) Now for your problem: V= 550(cos295 N +sin295 E)+28(cos109 N+ sin109) combine N, E vector ...
*Sunday, April 29, 2012 at 2:49pm*

**Honors Trig.**

A plane is flying at a speed and direction of 550 mph, 25 degrees north of west. There is a wind of 28 mph, at an angle of 19 degrees south of the east direction. How fast is the plane actually flying? What direction is the plane traveling?
*Sunday, April 29, 2012 at 2:38pm*

**Maths trig**

Whats the workings out to get to these answers ? Jw ta
*Sunday, April 29, 2012 at 12:29pm*

**Maths trig**

Thanks :)
*Sunday, April 29, 2012 at 12:27pm*

**Maths trig**

sin2t = 2 sint cost sin3t = sint cos2t + cost sin2t (cos2t = 1 - 2sin^2 t)
*Sunday, April 29, 2012 at 10:50am*

**Maths trig**

Use compound angle formulae to express Second harmonic i2= sin2t and the the third harmonic i3=sin3t in terms of the first harmonic sint
*Sunday, April 29, 2012 at 2:06am*

**algebra2/trig**

1) looks like you are dealing with the cubes so term(n) = n^3 2) did you notice that each term is one less than a perfect square? e.g. 3 = 2^2 - 1 --term(1) 8 = 3^2 -1 -- term(2) 15 = 4^2 -1 24 = 5^2 - 1 35 = 6^2 - 1 so term(n) = (n+1)^2 -1
*Saturday, April 28, 2012 at 10:43pm*

**algebra 2/trig**

1) a (n ) = n ^ 3 1 ^ 3 = 1 2 ^ 3 = 8 3 ^ 3 = 27 4 ^ 3 = 64 5 ^ 3 = 125 6 ^ 3 = 216 2 ) a (n ) = n ^ 2 + 2 n 1 ^ 2 + 2 * 1 = 1 + 2 = 3 2 ^ 2 + 2 * 2 = 4 + 4 = 8 3 ^ 2 + 2 * 3 = 9 + 6 = 15 4 ^ 2 + 2 * 4 = 16 + 8 = 24 5 ^ 2 + 2 * 5 = 25 + 10 = 35 6 ^ 2 + 2 * 6 = 36 + 12 = 48
*Saturday, April 28, 2012 at 10:31pm*

**TRIG**

one rotation is 5π ft so the hypotenuse has length 5π and sin 15 = height/(5π) height = 5π sin 15° = ......
*Saturday, April 28, 2012 at 10:12pm*

**algebra 2/trig**

Write the next term of sequence,and then write the rule for the nth term. 1)1,8,27,64,....125 the nth is 2) 3,8,15, 24,.....35 the nth is Can you help me and correct ? thank
*Saturday, April 28, 2012 at 9:16pm*

**TRIG**

5. A wheel 5.00 ft in diameter rolls up a 15.0° incline. How far above the base of the incline is the top of the wheel after the wheel has completed one revolution? A. 4.07 ft B. 13.1 ft C. 8.13 ft D. 9.07 ft
*Saturday, April 28, 2012 at 9:05pm*

**algebra2/trig**

Write the next term of sequence,and then write the rule for the nth term. 1)1,8,27,64,....125 the nth is n 2) 3,8,15, 24,.....35 the nth is Can you help me and correct ? thank you
*Saturday, April 28, 2012 at 7:55pm*

**trig question**

Sorry, the web address is spaced out so you need to put it together..again sorry, but I really need the help. Much appreciated!
*Saturday, April 28, 2012 at 6:05pm*

**trig question**

Hi, my question is attached to the web below (picture), because I can't draw the diagram on here. Sorry for any inconvenience. Please help and thanks. imageshack . us/photo/my-images / 845 / img0043gx . jpg/
*Saturday, April 28, 2012 at 6:02pm*

**trig question**

But the question ask to find the area of AE and EB together
*Saturday, April 28, 2012 at 5:55pm*

**trig-math**

4. A carpenter wants to be sure that the corner of a building is square and measures 6.0 ft and 8.0 ft along the sides. How long should the diagonal be? A. 12 ft B. 10 ft C. 11 ft D. 14 ft 5. A wheel 5.00 ft in diameter rolls up a 15.0° incline. How far above the base of ...
*Saturday, April 28, 2012 at 4:32pm*

**math-TRIG**

i thank you for the one u did i have 40 of these i got the ans to the rest these are the one i could figure out so plz any help i acan get i thNK U a lot
*Saturday, April 28, 2012 at 3:40pm*

**math-TRIG**

1. Which angle measure is consistent with all of the following criteria? (i) The reference angle is 40°. (ii) The angle is more than one revolution. (iii) The angle's terminal side is in Quadrant II. (iv) The angle isn't positive. A. –580° B. –500°...
*Saturday, April 28, 2012 at 3:33pm*

**trig question**

sorry 1 = EO, the side along the x axis
*Saturday, April 28, 2012 at 3:31pm*

**trig question**

a 30,60 , 90 triangle has sides 1 =AO, sqrt 3 = EA and hypotenuse 2 AB = 2 sqrt 3 your angle AOB is 2*60 = 120 OE the altitude is 1 Your area = (1/2)(1)(2 sqrt 3) = sqrt 3
*Saturday, April 28, 2012 at 3:30pm*

**trig question**

NEW DIAGRAM: On a unit circle, sin x = square root 3 over 2, with center O. Vertical line from top to center of circle is PO. Horizontal line from middle to right of circle is OE. Another vertical line of AB is parallel to PO. And radius of circle (line from O to A) is 1 unit...
*Saturday, April 28, 2012 at 2:57pm*

**trig question**

On a unit circle, sin x = square root 3 over 2, with center O. Vertical line from top to center of circle is PO. Horizontal line from middle to right of circle is OE. Another vertical line of AB is parallel to PO. And radius of circle (line from O to A) is 1 unit. From A to E ...
*Saturday, April 28, 2012 at 2:49pm*

**math-TRIG**

1. Which angle measure is consistent with all of the following criteria? (i) The reference angle is 40°. (ii) The angle is more than one revolution. (iii) The angle's terminal side is in Quadrant II. (iv) The angle isn't positive. A. –580° B. –500°...
*Saturday, April 28, 2012 at 1:46pm*

**trig problem**

Hi, A fountain in a shopping centre has a single jet of water. The height of the jet of water varies according to a sinusoidal function. A student notes that, in exactly one minute, the jet goes from a minimum height of 2m to a maximum height of 6m and back to 2m. At 13:00, ...
*Saturday, April 28, 2012 at 1:27pm*

**Trig. application**

Hello.. In your previous solution to the question: "Dave is going for a ride on his unicycle. The radius of the wheel is 25.5cm. When he gets on, the valve of the wheel is at its maximum height. He pedals along a path at a speed of 30km/h. At what height will the valve be...
*Saturday, April 28, 2012 at 1:21pm*

**Trig. application**

One rotation of the wheel would cover 2(25.5)π or 51π cm 30 km/hr = 30(1000)(100) cm / 60 minutes = 50000 cm/min in 4 min Dave will have covered 4(50000) cm = 200,000 cm (using Distance = rate x time ) So the number of rotations = 200000/(51π) = 1248.274063 The ...
*Saturday, April 28, 2012 at 8:51am*

**math - trig**

Q. 1 c) -220 degrees. is -180 Plus(-40) degrees. It will be in Quadrant II Q. 2 a) 14.07 cms radius = 7.2 cm perimieter 2 x 3.14 x 7.2 = 45.216 cm angle is 112 degree 112/360x45.216 = 14.0672 or 14.07 cm Q.3 d) 21.833 50/60 is 0.833 (nearest thousandth)
*Saturday, April 28, 2012 at 5:26am*

** math - trig**

1.Which angle measure is consistent with all of the following criteria? (i) The reference angle is 40°. (ii) The angle is more than one revolution. (iii) The angle's terminal side is in Quadrant II. (iv) The angle isn't positive. A. –580° B. –500°...
*Saturday, April 28, 2012 at 4:06am*

**Trig. application**

Dave is going for a ride on his unicycle. The radius of the wheel is 25.5cm. When he gets on, the valve of the wheel is at its maximum height. He pedals along a path at a speed of 30km/h. At what height will the valve be located after he has cycled for 4 minutes? How do I find...
*Saturday, April 28, 2012 at 1:01am*

**Trig Help!**

you got it backwards π/12 = (1/2) of π/6 using cos 2A = cos^2 A - sin^2 A = 2cos^2 A - 1 so cos π/6 = 2 cos^2 π/12 - 1 √3/2 + 1 = 2cos^2 π/12 cos^2 π/12 = √3/4 + 1/2 = (√3 + 2)/4 cos π/12 = √(√3+2) /2 check: by ...
*Saturday, April 28, 2012 at 12:13am*

**Trig Help!**

Question: Trying to find cos π/12, if cos π/6 = square root 3 over 2, how to find cos π/12 using DOUBLE angle formula? This is what I got so far.. cos 2(π/6) = cos (π/6 + π/6) = (cos π/6)(cos π/6) - (sin π/6)(sin π/6) = cos^2...
*Friday, April 27, 2012 at 11:59pm*

**Solving Trig equation**

you should recognize that they are using the formula tan(A+B) = (tanA + tanB)/(1 - tanAtanB) so (tanx + tan π/3)/(1 - tanxtan(π/3) = √3 becomes tan(x+π/3) = √3 , I know tan 60° or tan 240° = √3 OR tan π/3 or tan 4π/3 = √...
*Friday, April 27, 2012 at 11:56pm*

**Solving Trig equation**

Solve the trig equation exactly in the interval 0≤x≤2π. tan x + tan π/3 ------------------ = square root 3 1 - tan x tan π/3
*Friday, April 27, 2012 at 11:41pm*

**trig**

the amplitude is 3 you can determine the max/min by simply observing the properties of the cosine curve the max of cos(anything) is 1 and its minimum is -1 so max of 4cos(.....) is s4 and its minimum is -4 so max of -3 + 4cos(....) is 1 and its min is -7
*Friday, April 27, 2012 at 7:47am*

**trig**

Consider the trigonometric function f(t) = -3+4cos(pi/3(t-3/2)) What is the amplitude/period of f(t)? What are the maximum and minimum values attained by f(t)?
*Friday, April 27, 2012 at 3:28am*

**alg2/trig**

im assuming oyu saying cos75 degree as a simple fraction; cos(75)=cos(45+30) recall the formula cos(a+b)=cos a cosb- sin a sin b cos(45+30)=cos(30)sin(45)- sin(30)sin(45) cos(45+30)=((sqrt(3))/2)((sqrt(2))/2)-… cos(45+30) =(sqrt(6)- sqrt(2))/4
*Friday, April 27, 2012 at 1:05am*

**alg2/trig**

how would you express cos(75 as a single fraction?
*Thursday, April 26, 2012 at 11:11pm*

**Trig Question**

construct a triangle in quad II with x=-4 and y = 3 since tanØ = y/x or opposite/adjacent so r^2 = (-4)^2 + 3^2 r = 5 sinx = 3/5 and cosx = -4/5 you have to know that sin 2x = 2sinxcosx = 2(3/5)(-4/5) = -24/25 cos 2x = cos^2 x - sin^2 x = 16/25 - 9/25 = 7/25 tan 2x = ...
*Thursday, April 26, 2012 at 5:56pm*

**Trig Question**

Given that tan x= -3/4 and x is in the second quadrant. Find sin 2x, cos 2x, and tan 2x (Exact, no decimals). Please show step-by-step, thank you!
*Thursday, April 26, 2012 at 4:55pm*

**trig**

I don't think the identity holds. Plug in x = pi/6. Graph (sec6x+sin2x)/(sin6x-sin2x)-tan4xcot2x and you don't get zero.
*Wednesday, April 25, 2012 at 12:00pm*

**trig**

(sec6x+sin2x)/(sin6x-sin2x)=tan4xcot2x
*Wednesday, April 25, 2012 at 11:26am*

**trig**

sin ( x ) = 5 / 12 cos ( x ) = + OR - sqrt [ 1 - sin ^ 2 ( x ) ] cos ( x ) = + OR - sqrt [ 1 - ( 5 / 1 3 ) ^ 2 ] cos ( x ) = + OR - sqrt ( 1 - 25 / 169 ) cos ( x ) = + OR - sqrt ( 169 / 169 - 25 / 169 ) cos ( x ) = + OR - sqrt ( 144 / 169 ) cos ( x ) = + OR - 12 / 13 In ...
*Tuesday, April 24, 2012 at 5:13pm*

**trig**

Prove that if Sinx=5/13 and Siny=12/13, where x and y angles in Q1, then Sin(x+y)=1
*Tuesday, April 24, 2012 at 4:55pm*

**trig**

2tanc - 3 = 3tanc - 4 -3 = tanc - 4 1 = tanc ** Plug in Graphing Calculator: arctan (1) = 45 45 + 180 = 225 Ans. : 45 and 225.
*Monday, April 23, 2012 at 8:55pm*

**trig**

Could be a dot product (scalar product) or could be a vector product (cross product) If a dot product then 6*-3 + 7*9 = 45 If a cross product then i j k 6 7 0 -3 9 0 do determinant k (6*9 -(7*-3) ) = k (54+21) = 75 in z direction
*Monday, April 23, 2012 at 7:27pm*

**trig**

find the math product of u and v u= (6,7) v= (-3,9)
*Monday, April 23, 2012 at 7:19pm*

**trig**

When does the period occur and the phase shift?
*Monday, April 23, 2012 at 5:48pm*

**trig**

150
*Sunday, April 22, 2012 at 8:57pm*

**pre-calculus**

@Adam: if these kinds of problems are hard for you to understand (i know they are for me)try algebra-dot-com. Type your question in the google custom search box. They have some problems in the archives. If they don't have the ones you're looking for, go back to the ...
*Sunday, April 22, 2012 at 7:39pm*

**trig**

when is 3 x = 2 pi ?
*Sunday, April 22, 2012 at 6:03pm*

**trig**

2sec(3x-(pi/3)) Find the period.
*Sunday, April 22, 2012 at 5:56pm*

**Trig. - Nope**

My bad. Reiny is correct. Can you see my mistake?
*Saturday, April 21, 2012 at 5:39pm*

**Trig.**

x^2-3x-28 = (x+3)(x-7) x^2-x-42 = (x+6)(x-7) x^2+10x+24 = (x+6)(x+4) x^2+x-12 = (x-3)(x+4) so, you are evaluating (x+3)(x-7)/(x+6)(x-7) - (x+6)(x+4)/(x-3)(x+4) = (x+3)/(x+6) - (x+6)/(x-3) LCD is (x+6)(x-3) [(x+3)(x-3) - (x+6)(x+6)]/(x+6)(x-3) = (x^2 - 9 - x^2 - 12x - 36)/(x+6...
*Saturday, April 21, 2012 at 5:38pm*

**How is this trig ?? - Trig.**

factor it ... (x^2-3x-28)/(x^2-x-42) -(x^2+10x+24)/(x^2+x-12) = (x-7)(x+4)/((x-7)(x+6)) - (x+6)(x+4)/((x+4)(x-3)) = (x+4)/(x+6) - (x+6)/(x-3) = [(x+4)(x-3) - (x+6)(x+6)]/((x+6)(x-3)) = ((x^2+x-12)-(x^2+12x+36)]/((x+6)(x-3)) = (-11x - 48)/(x+6)(x-3) = -(11x+48)/(x+6)(x-3)) ...
*Saturday, April 21, 2012 at 5:34pm*

**Trig.**

the way you typed it .... 0 = √20 ---> silly statement, thus no solution if you meant: 6x = √(20+6x) then square each side 36x^2 = 20+6x 36x^2 - 6x - 20 = 0 (6x - 5)(6x + 4) = 0 x = 5/6 or x = -2/3 since we squared, all answers must be verified if x = 5/6 LS = 6...
*Saturday, April 21, 2012 at 5:17pm*

**Trig.**

Are you kidding? 6 x = sqrt ( 20 ) + 6 x 6 x - 6 x = sqrt ( 20 ) 0 = sqrt ( 20 ) ???????????
*Saturday, April 21, 2012 at 5:12pm*

**Trig ???**

d(P) = -8x + 8 = 0 for a max/min of P 8x = 8 x = 1 when x = 1 P = -4+ 8+7 = 11 I will leave it up to you to interpret the answer and state the conclusion
*Saturday, April 21, 2012 at 5:10pm*

**Trig.**

Solve. Check for extraneous solution. 6x= √20+6x
*Saturday, April 21, 2012 at 2:15pm*

**Trig**

Dalco manufacturing estimate that its weakly profit, P, in hundreds of dollars,can be approximated by the formula P= -4x²+8x+7, where x is the number of units produced per week, in thousands. 1)How many units should the company produce per week to earn maximum profit 2)...
*Saturday, April 21, 2012 at 1:53pm*

**Trig.**

Subtract. Simplify is possible. (x^2-3x-28)/(x^2-x-42) -(x^2+10x+24)/(x^2+x-12)
*Saturday, April 21, 2012 at 1:36pm*

**Trig**

LS = (sin^2 t + cos^2 t)(sin^2 t - cos^2 t)/(sin^2 t cos^2 t) = 1(sin^2 t - cos^2 t)/(sin^2 t cos^2 t) = sin^2 t/(sin^2 t cos^2 t) - cos^2 t/(sin^2 t cos^2 t) = 1/cos^2 t - 1/sin^2 t = sec^2 t - csc^2 t = RS
*Thursday, April 19, 2012 at 9:58pm*

**Trig**

sin^4t-cos^4t/sin^2t cos^2t= sec^2t-csc^2t i have =(sin^2t+cos^2t)(sin^2t+cos^2t)/sin^2tcos^2t then do i go =(sin^2t+cos^2t)/sin^2tcos^2t stumped
*Thursday, April 19, 2012 at 8:26pm*

**algebra2/trig**

4.8 hours
*Thursday, April 19, 2012 at 7:36pm*

**Alg2/Trig**

n * log ( a ) = log ( a ^ n ) log ( a ) + log ( b ) = log ( a * b ) log ( a ) - log ( b ) = log ( a / b ) 2 * log ( y ) = log ( x ^ 2 ) log( x ) + 2 * log ( y ) - log ( z ) = log ( x * y ^ 2 / z )
*Thursday, April 19, 2012 at 6:34pm*

**Alg2/Trig**

Write the log as a single function: logx + 2logy - logz
*Thursday, April 19, 2012 at 6:20pm*

**Trig?Precalc**

Do you not recognize the equation as that for a circle of radius √6 ? its center is at (0,0), so it's the most basic of any polar equation: r = 6 FYI, if you want us to show our work, show us how far you got, so we know where to concentrate the help.
*Thursday, April 19, 2012 at 4:41pm*

**Trig/Precalc**

YOu will have to use logarithms take ln of both sides ln 6 = ln (e^0.2t) ln6 = .2t lne, but lne = 1 t = ln6/.2= appr 8.959
*Thursday, April 19, 2012 at 4:14pm*

**Trig/Precalc**

solve 6=e^0.2t Round your answer to the nearest hundredth Someone please help me - I don't understand this problem at all!
*Thursday, April 19, 2012 at 12:55pm*

**Trig?Precalc**

write the rectangular equation x^2+y^2=6 in polar form. I do not want people to just post the answer! Please, show your work so that I can understand how to do these kinds of problems myself! Thank you and God Bless!
*Thursday, April 19, 2012 at 12:40pm*

**trig**

Wb = mg = 100kg * 8.8N/kg = 980 N. = Wt. of box. Fb = 980N @ 20 Deg. = Force of the box. Fp = 980*sin20 = 335.2 N. = Force parallel to ramp. Fv = 980*cos20 = 920.9 N. = Force perpendicular to ramp. Fk = Force of kinetic frictin. Fn = Fp - Fk = ma 335.2 - Fk = 100*0. 335.2 - Fk...
*Wednesday, April 18, 2012 at 10:40pm*

**algebra-trig help asap**

x= arcsec 2= arccos1/2=60deg
*Wednesday, April 18, 2012 at 9:23pm*

**algebra-trig help asap**

x=sec^-1 2 I really need help with this problem. Thanks
*Wednesday, April 18, 2012 at 8:06pm*

**algebra-trig help asap**

=tan (cos^-1(3/5) =tan(theta) =4/3
*Wednesday, April 18, 2012 at 7:56pm*

**algebra-trig help asap**

Evaluate the expression. Assume that all angles are in Quadrant I. 14. tan(arccos 3/5)
*Wednesday, April 18, 2012 at 5:56pm*

**Trig - Please help**

Can anyone help with this question? Now suppose that, starting with the ﬁrst row of seats, the ﬂoor of the seating area is inclined at an angle of Theta = 25 degrees above the horizontal, and the distance that you sit up the incline is x, as shown in the ﬁ...
*Wednesday, April 18, 2012 at 5:24pm*

**algebra-trig help asap**

by definition, arccos(4/5) is the angle whose cosine is 4/5 so, cos(that angle) is . . . 4/5!
*Wednesday, April 18, 2012 at 4:44pm*

**algebra-trig help asap**

Evaluate the expression. Assume that all angles are in quadrant 1. 1. cos(arccos4/5)
*Wednesday, April 18, 2012 at 4:42pm*

**mth, trig**

If a is in QII, sin is positive, cos is negative. 7^2 + 24^2 = 25^2, so it's a 7-24-25 triangle If b is in QIV, sin is negative, cos is positive. 5^2 + 12^2 = 13^2, so it's a 5-12-13 triangle. what did you do to find the missing sin/cos values?
*Wednesday, April 18, 2012 at 4:25pm*

**math, trig**

Graph one period of the following function. Show all work . y=2sinx+2cosx
*Wednesday, April 18, 2012 at 2:13pm*

**mth, trig**

Thanks but how did you find that? My numbers came out completely different -_-
*Wednesday, April 18, 2012 at 2:05pm*

**mth, trig**

sin a = 24/25 cos b = 5/13 now apply addition formulas
*Wednesday, April 18, 2012 at 11:28am*

**trig**

If there are h feet of tower above the man's eyes, h/65 = tan35° so, the tower height is 7 + 65tan35° = 52.5 ft
*Wednesday, April 18, 2012 at 11:26am*

**trig**

a 7 foot tall man is standing 65 feet away from a tower. if the angle of elevation is 35 degrees. what is the height of the tower to nearest tenth of a foot?
*Wednesday, April 18, 2012 at 11:11am*

**mth, trig**

Given cos a=-7/25 in quadrant II , and sin b=-12/13, in quadrant IV , find cos(a+b) and sin2a
*Wednesday, April 18, 2012 at 11:10am*

**Trig**

Can anyone help with this question. Now suppose that, starting with the ﬁrst row of seats, the ﬂoor of the seating area is inclined at an angle of Theta = 25 degrees above the horizontal, and the distance that you sit up the incline is x, as shown in the ﬁ...
*Tuesday, April 17, 2012 at 4:49pm*

**Trig**

Lisa, saw that one last night, confused about the angle 'a' in xcosa and xsina. secondly where does x come in ? describe your triangle. I have a triangle with sides a and b and Ø as its contained angle.
*Tuesday, April 17, 2012 at 8:59am*

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