Wednesday
June 19, 2013

# Homework Help: Math: Trigonometry

trig
write the expression sin4xsin5x as a sum or difference of trigonometric functions
Monday, April 14, 2008 at 11:58am

trig
give the exact real number value without using a calculator sin[(cos^-1)(1/4)] sin[(tan^-1)(3/4)+(tan^-1)(12/5)]
Monday, April 14, 2008 at 11:37am

Math (Trig) a.s.a.p, thanks!
verify the identities: 1.) 2tanx-(1+tanx)^2 = -secx 2.) cos(x-330degrees)=1/2(ã3cos​x-sinx) *the ãis only over the 3* 3.) 1+cos2x/sinx=cotx any help is greatly appreciated!!
Thursday, April 10, 2008 at 8:43am

trig
What is the amplitude,phase shift and period of y=sin 2x? What is the amplitude, phase shift and period of y= sin2(x + 3.14/4)
Wednesday, April 9, 2008 at 7:12pm

Math (Trig)
sorry, another I can't figure out Show that (1-cot^2x)/(tan^2x-1)=cot^2x I started by factoring both as difference of squares. Would I be better served by writing in terms of sine and cosine? Such as: [1-(cos^2x/sin^2x)]/[(sin^2x/cos^2x)-1]=​(cos^2x/sin^2x)
Wednesday, April 9, 2008 at 2:06pm

Trig
Solve in terms of sine and cosine: sec(x) csc(x)- sec(x) sin(x) so far I have: 1/cos(x) 1/sin(x) - 1/cos(x) sin(x) I am not sure where to go to from there. The book says the answer is cot(x) or cos(x)/sin(x) Thank you in advance.
Wednesday, April 9, 2008 at 10:36am

trig
Tuesday, April 8, 2008 at 10:08pm

trig
A geologist stands on the shore of a lake in Ontario with a theodolite and finds that the angle of inclination to the top of a distant rock pillar is 28.5 degrees. He then walks 10 m along the shore at a 90 degree angle to his measurment, and finds that the angle to the same ...
Tuesday, April 8, 2008 at 10:05pm

trig
Find all angles of a right triangle RST given that r = 18cm and s=20 cm
Tuesday, April 8, 2008 at 10:02pm

trig
If a triangle has angles 35 and 65 degrees, what is the measurment of the third angle? Is it a right triangle?
Tuesday, April 8, 2008 at 10:01pm

trig
Work out the following identities a)sin pheta / cos pheta b)tan pheta cos pheta
Tuesday, April 8, 2008 at 10:00pm

trig
If a = 5 cm and b = 3cm, use the Pythagorean Theorem to find c
Tuesday, April 8, 2008 at 9:59pm

trig
I have heard that trig CAN be super easy, that there are just, like, 10 rules you need to memorize then all the problems are easy. ... Does anyone know what these are? Thanks!
Monday, April 7, 2008 at 12:20am

math [basic trig]
Sam and Markus are standing on level ground 100m apart. A large tree is due North of Markus and on a bearing of 065degrees from Sam. The top of the tree appears at an angle of elevation of 25 degrees to Sam and 15 degrees to Markus. Find the height of the tree.
Tuesday, March 25, 2008 at 8:34pm

trig
Am I right on this? 2sec^2(2x)-8=0 2sec^2(2x)=8 divide by 2 sec^2(2x)=4 find square root sec(2x)=2 Now, would this simply be asking me to find where secant is equal to one? Or is there no solution because secan't (pun intended) be equal to anything above 1?
Sunday, March 23, 2008 at 6:34pm

trig
2sin(x)cos(x)+cos(x)=0 I'm looking for exact value solutions in [0, 3π] So I need to find general solutions to solve the equation. But do I eliminate cos(x), like this... 2sin(x)cos(x)+cos(x)=0 2sin(x)cos(x)= -cos(x) 2sin(x) = -1 sin(x) = -1/2 at 4pi/3 and 5pi/3 and ...
Sunday, March 23, 2008 at 4:52pm

trig
I am having trouble figuring these two out The directions say find all solutions to the triangles described below. Round each angle to the nearest degree and the length of the missing side to the nearest tenth at the end of the computations C= 27 degrees 50 minutes, c= 349 m, ...
Wednesday, March 19, 2008 at 4:42pm

trig
eliminate the parameter t from the following x = 4 sin t y= 7 cos t sketch the graph
Friday, March 14, 2008 at 1:27pm

trig
eliminate the parameter t from the following x = 9sin t y = 9cos t
Friday, March 14, 2008 at 1:26pm

trig
Write an expression that gives all solutions to the equation sin x + cos x = - radical 2
Friday, March 14, 2008 at 10:29am

Trig
Solev the equation for t if 0 is less than or eual to t which is less than 2 pi 7sin + radical3 = 5 sin t
Thursday, March 13, 2008 at 10:50am

Trig
Find the exact value of: cos315. I have to use the sum angle formula cos(270+45) cos270 cos45 - sin270 sin45 thats all I have. Is the answer at least sqrt 2/2?
Friday, March 7, 2008 at 10:00pm

Trig
Simplify: (1/secx+sin^2x/cosx)cosx. Explain alittle bit, not just do the steps please.
Friday, March 7, 2008 at 9:45pm

Trig
Find secx if sinx = -4/5 and 270 < x < 360. tan^2x+1=sec^2x (-4/5)^2+1=sec^2x 16/25+1=sec^2x 17/25=sec^2x sqrt 17/5 I don't know if it should be positive or negative.
Friday, March 7, 2008 at 9:42pm

Trig
State the vertical shift and the equation of the midline for y=4cosx-1. k = -1 y = -1 vertical shift = -1 midline equation is y=-1
Friday, March 7, 2008 at 9:27pm

Trig
Find the amplitude, if it exists, and the period of: y=tan1/4x. no amplitude I got confused, is the period 4pi? And is that the same as saying 360 degrees?
Friday, March 7, 2008 at 9:22pm

Trig(Last 6 questions to check. Thanks to EVERYONE
Find the amplitude, if it exists, and the period of: y=cos3x. |a|=|1| amplitude = 1 period = 360/b period = 360/3 period = 120 degrees
Friday, March 7, 2008 at 9:19pm

Trig
Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (x=theta BTW)
Friday, March 7, 2008 at 1:51pm

Trig
Solve: x=Arctan(-sqrt3).
Friday, March 7, 2008 at 1:44pm

Trig
P(-15/17,-8/17) is found on the unit circle. Find sin theta and cos theta. P(-15/17,-8/17)= P(cos theta,sin theta) sin=-8/17 cos=-15/17
Friday, March 7, 2008 at 1:42pm

Trig
Should the triangle be solved beginning with Law of Sines of Law of Cosines. Then solve the triangle. Round to the nearest tenth. A=56 degrees, B=38 degrees, a=13. Sines. I get confused on the formula. I know C=86 degrees
Friday, March 7, 2008 at 1:38pm

Trig
Should the triangle be solved beginning with Law of Sines of Law of Cosines. Then solve the triangle. Round to the nearest tenth. a=16, b=13, c=10. Cosines A=93 degrees, B=54 degrees, C=33 degrees
Friday, March 7, 2008 at 1:34pm

Trig
In triangle ABC, A=35 degrees, a=43, and c=20. Determine whether ABC has no solution, one solution, or two solutions. Then solve the triangle. Round to the nearest tenth. no solution.
Friday, March 7, 2008 at 1:30pm

Trig
Find the area of ABC if A=56 degrees, b=20ft, and c=12ft. 1/2(20)(12)sin56 1/2(240)sin56 99.5
Thursday, March 6, 2008 at 6:02pm

Trig
Find the exact value of: sin60-cos60. do I just type sin60-cos60 in my calculator? = .37
Thursday, March 6, 2008 at 5:59pm

Trig
Find the exact value of: tan(-3pi).
Thursday, March 6, 2008 at 5:56pm

Trig
Find the exact value of: sin405. reference angle=225 sin225= -.707106781 = -.71
Thursday, March 6, 2008 at 5:53pm

Trig
Find the exact value of cot(-pi/6). I don't have a lot of work for this one all I have is 30 I guess that was suppose to be the reference angle. answer .58
Thursday, March 6, 2008 at 5:51pm

Trig
Find the exact values of the six trigonometric functions 0 if the terminal side of 0 in standard position contains the points(-5,-4). (0 is not the number zero I don't know what its called) I have to find r first. r=sqrt x^2+y^2 r=sqrt -5^2+-4^2 r=sqrt 41 sin=y/r sin=-4/...
Thursday, March 6, 2008 at 3:30pm

Trig
Find one angle with positive measure and one angle with negative measure coterminal with -310 -310+360=50 -310-360=-670 so 50,-670
Thursday, March 6, 2008 at 3:18pm

Trig
Rewrite 9pi/5 radians in degree measure. 9pi/5 =9pi/5(180/pi radians) =1620/5 =324 degrees
Thursday, March 6, 2008 at 3:14pm

Trig
Thursday, March 6, 2008 at 3:06pm

Trig
Solve ABC if C=90 degrees, B=20 degrees, and b=10. Round measures of side to the nearest tenth and measures of angles to the nearest degree. So all I need to do for this problem is find A,a,c right? I know that A=70 b/c 90+20=110 and 180-110=70 but how do I find a,c?
Thursday, March 6, 2008 at 2:59pm

pre-cal/trig
PlEASE hlep me with this!! I need it as soon as possible....... cos(x-(pi/4))+sin(x-(pi/4))=1 Find the answer from 0 to 2pi. When I slove this, I got cosx+sinx=(1/ square root of 2). then I don't know what to do the rest. Please help me.
Tuesday, March 4, 2008 at 7:44pm

Trig
Hi. Can somebody help me solve this equaton with EXACT answers? ----- sin3x = 0 ----- Thankyou! All help is appreciated.
Monday, March 3, 2008 at 12:47am

Trig
Can somebody please help me find the domain of: 1 / cos4x If there are any working out, could you be kind enough to show your steps? Thankyou. All help is of course, appreciated.
Saturday, March 1, 2008 at 2:27am

Trig Equation
Solve for x (exact solutions): sin x - sin 3x + sin 5x = 0 -¦Ð ¡Ü x ¡Ü 0 ------ Now, using my graphics calculator, I discovered that the following equation has 5 solutions. I have managed to come up with 3 of them but I'm having trouble ...
Saturday, March 1, 2008 at 1:52am

Trig
Verify that each of the following is an identity. tan^2x-sin^2x=tan^2xsin^2x I can get it down to cos^2 on the right, but cannot get it to work out on the left. secx/cosx - tanx/cotx=1 On the left I got down to 1-tan^2, but that clearly doesn't equal 1.... 1-2cos^2x/...
Thursday, February 28, 2008 at 5:01pm

trig
8 sin 9x cos3x Rewrite the xpression as a sum or differnce using one of the product sum formulas Simplify if possible
Thursday, February 28, 2008 at 1:51pm

trig
Prove the identity sin squared 0 with line/2 = csc zero with line -cot zero with a line /2csc zero with a line
Thursday, February 28, 2008 at 1:50pm

trig
Use half-angle formulas to find the exact value for the following cot 75 degrees
Thursday, February 28, 2008 at 1:48pm

trig
Graph the followiing function from x + 0 to x = 4 pi y = 3 cos squared x/2
Thursday, February 28, 2008 at 1:47pm

trig
If cos A =1/3 with A in QIV find cscA/2
Thursday, February 28, 2008 at 1:46pm

trig
Prove the identity sin(3 pi /2 + x) + sin(3pi/2 -x) = -2cosx
Thursday, February 28, 2008 at 1:46pm

trig
If tan(A+B) = 2 and tan B =1/3, find tan A
Thursday, February 28, 2008 at 1:44pm

trig
Graph one complete cycle of y + cos x cos pi over6 + sin x sin pi/6 by first rewriting the right side in the form cos(A-B)
Thursday, February 28, 2008 at 1:43pm

trig
Graph the following from X = 0 to x = 2 pi 2cos 6x cos4x + 2 sin 6x sin 4x
Thursday, February 28, 2008 at 1:28pm

trig
Prove the identity sin (3 pi/2 + x) + sin (3 pi/2 -x) = -2 cos x
Tuesday, February 26, 2008 at 1:26pm

trig
If sin = -3/5 with A in QIV, find cos A/2
Tuesday, February 26, 2008 at 1:25pm

trig
If sin = 4/5 with A in QII, and sin B = -3/5 with B in QIV find cos(A-B)
Tuesday, February 26, 2008 at 1:24pm

trig
Tuesday, February 26, 2008 at 11:26am

Trig word problem
A park ranger at point A sights a redwood tree at point B at an angle 23 degrees from a fire tower at point C, From the fire tower, the Angle between the ranger and the tree is 123 degrees. If the ranger at point A is 2.3 miles from the fire tower at point C, how far is it ...
Sunday, February 24, 2008 at 9:42pm

trig
In triangle ABC, find <A to the nearest tength of a degree is m<B=95 degrees , b=15.4, a=8.0
Sunday, February 24, 2008 at 9:35pm

trig
Two ships, one sailing at 30 km/hr and the other at 45 km/hr, left port at the same time. Three hours later they were 120 km apart. If you had to find the angle between their courses an equation that could be used to solve this problem is:
Sunday, February 24, 2008 at 9:16pm

trig
transform the expression on left to one on right csc x-sin x to cot x cos x
Tuesday, February 19, 2008 at 11:24pm

Math: Calculus - Vectors
A boat travels at a speed of 5 m/s in still water. The boat moves directly across a river that is 70m wide. The water in the river flows at a speed of 2 m/s. How long does it take the boat to cross the river? In what direction is the boat headed when it starts the crossing. ...
Tuesday, February 19, 2008 at 10:29pm

trig
tanx=cotx
Monday, February 18, 2008 at 11:05pm

Trig
Find the exact value of sinx/2 if cosx = 2/3 and 270 < x < 360. A)1/3 B)-1/3 C)sqrt 6/6 D)-sqrt 6/6 C, since I KNOW cosx is always positive but I don't know the work involved. I know the half angle formula
Friday, February 15, 2008 at 5:53pm

Trig
Find the exact value of sin2(theta) if cos(theta) = -sqrt 5/3 and 180 < theta < 270. A)-1/9 B)-4 sqrt 5/9 C)1/9 D)4 sqrt 5/9 B? sin^2(theta) + cos^2(theta) = 1 sin^2(theta) = 1 - cos^2(theta) sin^2(theta) = 1 - (sqrt 5/3)^2 sin^2(theta) = 1 - (sqrt 25/9)
Friday, February 15, 2008 at 4:54pm

Trig
Which expression equivalent to: cos(theta + pi/2). A)cos theta B)-cos theta C)sin theta D)-sin theta my book doesnt give examples of this but my crack at it would be C b/c distributive property? and 2cos theta = sin theta
Friday, February 15, 2008 at 2:23pm

Trig(continued)
2)Find the solution of sin2 theta = cos theta if 0 -< theta < 180 A)30 degrees and 90 degrees B)30 degrees and 150 degrees C)30 degrees, 90 degrees, 150 degrees D)0 degrees, 90 degrees, and 150 degrees sin2 theta = cos theta sin2 theta - 1 = 0 (sin theta + 1)(sin theta...
Friday, February 15, 2008 at 12:52pm

Trig(3 all with work)
1)Find the exact value of cos 105 by using a half-angle formula. A)sqrt 2 - sqrt 3 /2 B)-sqrt 2 - sqrt 3 /2 C)-sqrt 2 + sqrt 3 /2 D)sqrt 2 + sqrt 3 /2 cos 105 cos 105 = cos 210/2 sqrt 1 + 210/2 sqrt 1 + sqrt 3/2 /2 sqrt 2 + sqrt 3/2 which is D 2)Find the solution of sin2 theta...
Friday, February 15, 2008 at 3:17am

Trig functions
1)Write the equation sin y= x in the form of an inverse function. A)y=Sin-1x B)x=Sin-1y C)y=sin-1x D)y=Sinx I chose A 2)Solve y=Arcsin1/2 A)-5pi/6 B)5pi/6 C)-pi/6 D)pi/6 I chose D 3)Find the value of Sin-1(-1/2) A)-30 degrees B)30 degrees C)150 degrees D)330 degrees I chose A ...
Tuesday, February 12, 2008 at 3:54pm

Trig functions and such
1)Find the exact value of cot(-315) A)1 B)square root of 2 C)square root of 2 over 2 D)2 I chose C 2)Find the exact value of sin(-pi/6) A)-1/2 B)-square root of 3/2 C)-square root of 2/2 D)square root of 2/2 I chose A 3)In triangle ABC, C=30, c=22, and b=42. Find B. A)73 ...
Monday, February 11, 2008 at 11:49am

trig
Determine the height of a tree which casts a shadow of 13.7m when the sun is at an angle of 28 degrees.
Sunday, February 3, 2008 at 10:21pm

trig
i vertex has no segment, 2 vertex have 1 segment , 3 vertex have 3 segments, 4 vertex have 6 segment , 5 vertex have 10 segments, how many segments are needed to connect 20 points?
Sunday, January 27, 2008 at 1:48pm

trig
if sin2x=3sin2y, prove that: 2tan(x-y)=tan(x+y)
Wednesday, January 23, 2008 at 11:44am

physics
A particle moves in a circle in such a way that the x- and y-coordinates of its motion are given in meters as functions of time t in seconds by: x=5cos(3t) y=5sin(3t) What is the period of revolution of the particle? Here's what my train of thought was... dy/dt over dx/dt ...
Sunday, January 20, 2008 at 9:00pm

calculus
Assuming that: Definite Integral of e^(-x^2) dx over [0,infinity] = sqrt(pi)/2 Solve for Definite Integral of e^(-ax^2) dx over [-infinity,infinity] I don't know how to approach the new "a" term. I can't use u-substitution, integration by parts, partial ...
Monday, January 14, 2008 at 1:46pm

ALG 2/Trig
A new $12,000 automobile decreases in value every year. What is it's value 7 years from now? Saturday, January 12, 2008 at 10:22pm Trig Please EXPLAIN the steps on how to solve these problems. Please provide detailed steps. A rectangle picture is 12 by 16 inches. If a frame of uniform width contains an area of 165 square inches, what is the width of the frame? The length of a rectangular garden is 6 feet more ... Thursday, January 10, 2008 at 11:24pm Trig. Please solve this equation. As you write down the steps, please give me a description on what you did. y^3 - 16y^3/2 + 64 = 0 Wednesday, January 9, 2008 at 8:55pm calculus Integrate x/(x^2 + 4) dx via trig substitution and by u=x^2+4 substitution. Show that results are equal. Via trig substitution of x=2 *tan t, I get: 1/2 * tan^-1 (x/2) + c Via u = (x^2 + 4) substitution, I get: 1/2 * ln |x^2 + 4| + c How are these equal? Monday, December 31, 2007 at 3:52pm math(trig) i need to figure out how to write the formula for the following question In a right triangle a = 30 yds and t5an A = 2. Find b and c. I have the answers but do not know how to write the formula. Can you help me ? Tuesday, December 18, 2007 at 10:22pm math (trig) Im having problems solving this equation: 2sin(x) = cos(x) + 2 I keep getting an imaginary number..:/ Tuesday, December 18, 2007 at 8:02pm Math (Trig) Solve the equation for exact values of x. sin(x) = 1-2(sin(x))^2 Sunday, December 16, 2007 at 6:55pm trig. Jack and Jill ran a 400 meter race. Jill ran therace in 50 second and won by 5 meters; that is Jack had run only 295 meter when Jill crossed the finish line. They decide to race again,but this time Jill starts 5 meters behind the starting line. Assuming the both runner run at ... Friday, December 7, 2007 at 1:55pm Trig x[sqrt of 2] + 3x = 4 Tuesday, December 4, 2007 at 11:44pm trig how do you solve this problem? 1+sinØ/cosØ +cosØ/1+sinØ = 2secØ and cosß- cosß/1-tanß = sinßcosß/sinß-cos&szli​g; Tuesday, December 4, 2007 at 9:35pm Reposted: Maths - Trig I've been told that sin(c+h)=sin(c)xcos(h)+cos(c)xsin(h) but how? please explain Sunday, December 2, 2007 at 6:12pm trig solve this equation: 4x^3-4x^2+13x-6=0 note: that's suppose to be 4x to the third and 4x squared Saturday, December 1, 2007 at 11:13pm Maths-Trig How does sin(c+h)=sin(c)xcos(h)+cos(c)xsin(h) please explain Saturday, December 1, 2007 at 6:08pm Math - Solving Trig Equations What am I doing wrong? Equation: sin2x = 2cos2x Answers: 90 and 270 .... My Work: 2sin(x)cos(x) = 2cos(2x) sin(x) cos(x) = cos(2x) sin(x) cos(x) = 2cos^2(x) - 1 cos(x) (+/-)\sqrt{1 - cos^2(x)} = 2cos^2(x) - 1 cos^2(x)(1 - cos^2(x)) = 4cos^4(x) - 4cos^2(x) + 1 5cos^4(x) - 5cos^... Saturday, November 24, 2007 at 7:07pm Math - Solving Trig Equations Solve each equation for o is less than and/or equal to theta is less than and/or equal to 360 -- sin^2x = 1 = cos^2x -- Work: cos^2x - cos^2x = 0 0 = 0 -- Textbook Answers: 90 and 270 -- Btw, how would you isolate for cos^2x = 0? Would it be... x = cos^-1 square root of _____ ? Saturday, November 24, 2007 at 4:48pm Math - Solving for Trig Equations For the following equation, why cannot I not solve it? I keep getting an error. -- 2cosx - 3 = 0 -- I first isolated for "x" 2cosx-3 = 0 (2cosx/2) = (3/2) x = cos^-1(3/2) x = error? why? -- My textbook answer: 30 and 330 degrees -- Thursday, November 22, 2007 at 9:01pm Math - Solving for Trig Equations Solve the following equation for 0 less than and/or equal to "x" less than and/or equal to 360 -- cos^2x - 1 = sin^2x -- Attempt: cos^2x - 1 - sin^2x = 0 cos^2x - 1 - (1 - cos^2x) = 0 cos^2x - 1 - 1 + cos^2x = 0 2cos^2x - 2 = 0 (2cos^2x/2)= (-2/2) cos^2x = -1 cosx = ... Thursday, November 22, 2007 at 5:35pm Math - Solving Trig Equations Solve each equation on the interval: 0 is less than and equal to theta is less than and equal to 360 -- 2sin2x = 1 -- --- My Answers: Let y represent 2x 2siny = 1 2siny/2 = 1/2 siny = 1/2 y = sin^-1(1/2) y = 30 2x = 30 2x/2 = 30/2 x = 15 (Quadrant 1) Quadrant 2 180 - theta = ... Wednesday, November 21, 2007 at 8:23pm Math - Solving Trig Equations Solve each equation for 0 is less than and equal to "x" is less than and equal to 360 3sinx = 2cos^{2}x ----- I don't know how to solve this equation...this is what I have, but I don't know if I'm on the right track or not 3sinx = 1 - 2sin^{2}x 3sinx - 1... Wednesday, November 21, 2007 at 6:29pm Math - Trig - Double Angles Prove: cos4x = 8cos^4x - 8cos^2x + 1 My Attempt: RS: = 4cos^2x (2cos^2x - 1) + 1 = 4 cos^2x (cos2x) + 1 LS: = cos2(2x) = 2cos^2(2x) - 1 = (cos^2(2)) - cos^2(2x)) - 1 ----- Prove: 8cos^4x = cos4x + 4cos2x + 3 My Attempt: RS: = cos2(2x) + 4cos(2x) + 3 = 2cos^2(2x) - 1 + 2(4)cos^... Saturday, November 17, 2007 at 6:17pm Math - Trig - Double Angles Prove: sin2x / 1 - cos2x = cotx My Attempt: LS: = 2sinxcosx / - 1 - (1 - 2sin^2x) = 2sinxcosx / - 1 + 2sin^2x = cosx / sinx - 1 = cosx / sinx - 1/1 = cosx / sinx - sinx / sinx -- Prove: 2sin(x+y)sin(x-y) = cos2y - cos2x My Attempt: RS: = 1 - 2sin^2y - 1 - 2sin^2x = 1 - 1 - ... Saturday, November 17, 2007 at 5:37pm Trig Solve the following interval 0<_ (less than or equal to)0(Theta)<2pi: 1. sin0(theta) + sin2 0(theta) = 0 2. 2cos^20 (theta) + cos0 (theta) -1 = 0 Wednesday, October 24, 2007 at 11:00am math how do i solve this using trig identities? 2 csc^2x = 3 cot^2x-1 Tuesday, October 16, 2007 at 11:10pm Pre Calculus/Trig find the area of a circle inscribed in triangle ABC where a=9, b=13, and the measure of angle C=38 degrees Thursday, October 11, 2007 at 9:04pm Trig does sin and tan repeat 2Pi as well? and what do csc sec an cot do? -2PI? Sunday, September 30, 2007 at 5:10pm Trig Evaluate the trigonometric function using its period as an aid. cos 5pi how would i go about finding the period and what is a period? Sunday, September 30, 2007 at 3:48pm Trig use a graphing utility to solve each equation, rounded to 2 decimal places 1. x^2 - 2sin2x = 3x 2. x^2 = x + 3cos2x Wednesday, September 26, 2007 at 12:17am Trig Solve the equation on the interval 0 less than or equal 0 < 2pi. 1. sec 30/2 = -2 2. cos(20 - pi/2) = -1 3. tan(0/2 + pi/3) = 1 Tuesday, September 25, 2007 at 12:41am Trig/Physics A car's wheel (with tire) is 26 inches in diameter and its center is 12 inches above the road. If the car is traveling at 60 feet per second, how fast is the highest point of the tire moving relative to the ground? Sunday, September 23, 2007 at 8:00pm Trig establish identity sec 0/1 + sec0 = 1 - cos0/sin^2 0 Thursday, September 20, 2007 at 12:49am Trig Establish the identity: 1. sin0(cot0 + tan0) = sec0 2. cos0 +1/cos0 -1 = 1 + sec0/1 - sec0 Thursday, September 20, 2007 at 12:47am Trig Use the half angle formula to find the exact value of tan 7 pie/8 Thursday, September 13, 2007 at 12:34am Trig if a tire is out of round so that the radius in a certain direction is 1 inch more than in the opposite direction, what is the difference in linear speed between these two points on the tire? Angular speed is 40 radians per second Wednesday, September 12, 2007 at 11:30am trig How fast is a bicycle traveling in feet per second if a wheel has a 21-in. diameter and the angular speed of the wheel is 33 radians per second? The speed of the bicycle is the same as the linear speed of a wheel. Tuesday, September 11, 2007 at 10:33pm Math Okay .. i have a trig question for some floor plans that im trying to do. I have a right angle . /| / | c / | a /___| b I have the lengths of side c and b. Both Being 28ft in length. What is the length of side a? The way you have drawn it, or tried to draw it, c is the ... Sunday, August 12, 2007 at 12:04am mathematics on sports can anyone provide me with some sources which has information on how mathematics has been used on sports? e.g., trig can help to calculate the best angle to throw a ball or something, the speed of running can affect the height of high jump etc. etc.? any help greatly ... Thursday, August 2, 2007 at 7:05am math (trig) Prove: sin^2(x/2) = csc^2x - cot^2x / 2csc^2(x) + 2csc(x)cot(x) On the right, factor the numberator as a difference of two perfect squares. In the denominator, factor out 2cscx. You ought to prodeed rather quickly to the proof. Monday, July 16, 2007 at 10:04am math (trig) Find sin(x/2) if sin(x)= -0.4 and 3pi/2 < or equal to (x) < or equal to 2pi Let's use cos 2A = 1 - 2sin2 A and we can match cos x = 1 - 2sin2 (x/2) so we will need cos x we know sin x = -.4 and x is in the fourth quadrant, so the cosine will be positive. Drawing a ... Sunday, July 15, 2007 at 11:51pm Calculus so we are doing integrals and I have this question on my assignment and I can't seem to get it, because we have the trig substituion rules, but the number isn't even so its not a perfect square and I jsut cant get it, so any help would be greatly appreciated. The ... Sunday, June 10, 2007 at 11:10pm Adv. Alg. w/Trig. I need help writing equations for these two word problems: 1. On June 30th, Mr. Hester will be given$1,000,000 and in July, Mr. hester will be paid $100,000 per day. 2. On June 30th, we will set up an account for Mr. Hester starting with$0.05. Every day in July, the ...
Monday, May 28, 2007 at 3:15am

I need help simplifying this expression: (3x^3y^5 + 6x^2y^-2/6x^5y^-2)^2 (3x^3y^5 + 6x^2y^-2/6x^5y^-2)^2 the second term has a y^-2 in the numerator and denominator, so.. (3x^3y^5 + 6x^2 /6x^5 )^2 (3x^3y^5 + 1 /x^3 )^2 I am not certain much more can be done to simplify it.
Friday, May 18, 2007 at 12:46am

Calculus
How would I find the antiderivative of this equation? S 0 to pi/3 (1-secxtans)dx This should be one that you should just recognize from your study of trig derivatives. Isn't the derivative of sec x, or (cos x)^-1 -(cos x)^-2(-sin x) ?? and isn't that sinx/cosx (1/cosx...
Wednesday, May 16, 2007 at 9:19pm

Trig
sin(2 tan-1 7/24) (that is inverse tangent) Draw a 7 24 25 right triangle. Label the angle whose tangent is 7/24. What is its angle? What is the sin of twice that angle.
Tuesday, May 15, 2007 at 4:28pm

precal
when i do the quadratic equation i get -17 plus or minus the square root of 193 all over 2. where do i get the two "cos 3x" roots?? solve the equation to the nearest tenth, where 0 degrees < or equal to x which is < 360 degrees. 8cos^2 3x-17cos3x+3=0 this ...
Monday, May 14, 2007 at 9:53pm

trig...again
gahh i cant figure this one out either. you have you verify the identity only using one side of the equation: sec^2x*sin^2x+sec^2x=-1 this identity cannot possible be true. on the left side you are adding 2 squared quantities, how can that result be negative? Check your typing...
Monday, May 7, 2007 at 9:14pm

trig
it says to verify the following identity, working only on one side: cotx+tanx=cscx*secx Work the left side. cot x + tan x = cos x/sin x + sin x/cos x = (cos^2 x +sin^2x)/(sin x cos x) = 1/(sin x cos x) = 1/sin x * 1/cos x You're almost there. thanks so much! i could not ...
Monday, May 7, 2007 at 8:57pm

trig help
I need help finding sinA if cosA=(-3/5) and A is greater than 90 degrees, but less than 180 degrees. Draw the quadrant diagram. In the upper left quadrant, greater then ninety degrees, but less than 180, cosine is neg, and sine is positive. Draw a three, four, five right ...
Sunday, May 6, 2007 at 8:01pm

calculus-integration!
should i use substitution?? if yes how should should i use it? plz i need some directions? k plz someone?...so far i used trig. substitution. i got a=8, so i used x=asin(è)so according to this substitution i got x=8sin(è) and dx=8cos(è) dè...then i ...
Sunday, May 6, 2007 at 4:25pm

Pre-calc
prove the identity: (cosx)(tanx + sinx cotx)=sinx+cos(squared)x i need steps to show how i got the answer generally, it is a good idea to change all trig ratios to sines and cosines, and start with the more complicated-looking side. so.... LS = cosx(sinx/cosx + sinx(cosx/sinx...
Sunday, May 6, 2007 at 1:53pm

math (final trig problem)
Solve for x on the interval [0,π/2): cos^3(2x) + 3cos^2(2x) + 3cos(2x) = 4 I havent done trig for a while so what exactly does that mean in solving for x on that interval and how would i go about doing that? Where are you getting these tough trig questions?? how about ...
Monday, April 30, 2007 at 10:33pm

math (more trig)
how could you do this problem? tinyurl 39jlf9 (sorry i cant get it to post because it is an internet address i cant seem to figure it out and it seems like there is not enough information or maybe i didnt pay attention in class i was able to get the one side that you can get ...
Monday, April 30, 2007 at 8:04pm

math (trig)
i have some problems doing trig the first one is: Show that cos(x/2) sin(3x/2) = ½(sinx + sin2x) i know that you are supposed to substitute all those trig function things in it but i kind of forgot how to the only that i can see substituting in is the double angle one ...
Monday, April 30, 2007 at 5:42pm

Math
The area of a regular pentagon with a perimeter of 35 units. Join the centre to each vertex to form 5 eq Join the centre to each vertex to form 5 equal triangles. Consider one of those triangles the central angle is 72º and each of the other two equal angles is 54º, ...
Sunday, April 29, 2007 at 3:19pm

Trigonometic
Solving Trigonometic Equations solve for x : 1)sinx = (4/5) 2) cosx = (-12/13) I will do the second one. first of all since the cosine is negative the angle must be in either the second or third quadrants. To find the "angle in standard position" take arccos(+12/13) ...
Monday, April 23, 2007 at 12:12pm

Trigonometic
Solving Trigonometic Equations 1)sinx = (4/5) 2) cosx = (-12/13) Solving Trigonometic Equations 1)sinx = (4/5) 2) cosx = (-12/13) What is the question? Solve for x? x= arcsin (4/5) put that in your calculator. Same for the next. For both cases I recognize the sides of well-...
Monday, April 23, 2007 at 5:52am

Math (Trig Question)
OK, I've been stuck on this question for like.. an hour. Prove how cos 2x = 1. Thanks for the help! Nvm... lol I got it. There was a typo. Sorry!
Sunday, April 22, 2007 at 9:10pm

Trig
I don't know the physics behind Snell's Law, but I can do the math Snell's Law says sin(angle of incidence)/sin(angle of reflection) = refractive index since you know the two angles... sin45/sin27 = refractive index =1.5575365 so for an angle of refection of 25&...
Thursday, April 19, 2007 at 6:08pm

Trig........
I need to prove that the following is true. Thanks (cosx / 1-sinx ) = ( 1+sinx / cosx ) I recall this question causing all kinds of problems when I was still teaching. it requires a little "trick" L.S. =cosx/(1-sinx) multiply top and bottom by 1+sinx, (creating the ...
Wednesday, April 18, 2007 at 11:02pm

Trig.......
I need to prove that the following is true. Thanks (2tanx /1-tan^x)+(1/2cos^2x-1)= (cosx+sinx)/(cosx - sinx) and thanks ........... check your typing. I tried 30º, the two sides are not equal, they differ by 1 oh , thank you Mr Reiny I'll tell my teacher this Question...
Wednesday, April 18, 2007 at 2:37pm

help, bobpursely
Please take a look at DEVON's trig equation at 9:14 I must be missing something obvious. If the second had been 3sin 2x it would be a straight forward question. The way it stands I was able to "reduce" it to the equation 8sin^4 x - 8sin^2 x + 3sin x + 2 = 0 I ...
Monday, April 16, 2007 at 10:54pm

trig
it says solve for all real solutions, compute inverse functions to 4 sigfigs. cos^2x=3-5cosx Devon, what grade level are these questions from? I am having the same problems as with your 9:14 post. Please see my partial solution in the post to bobpursely at 10:54 Devon, I have ...
Monday, April 16, 2007 at 9:57pm

trig
find the exact solutions 2cos^2x+3sinx=0 the way it stands, that is a "nasty" question. Are you sure the second term isn't 2sin(2x) ? no, its as i wrote it. then it's got me stymied, I must be missing something rather obvious, sorry! thanks for trying! 2cos^...
Monday, April 16, 2007 at 9:14pm

trig question
Compute inverse functions to four significant digits. cos^2x=3-5cosx cos^2x + 5cosx -3=0 now you have a quadratic, solve for cos x using the equation cosx=(-5 -+ sqrt (25 +12)/2 the back of the book says .9987+2kpi and -.09987+2kpi when i do it i dont get that answer. I get it...
Monday, April 16, 2007 at 8:27pm

Trig
solve to four decimal places 1.3224sinx + 0.4732=0 :for all real x values solve for sinx, then arcsinx. solve for sinx, then arcsinx. so its sinx= -.4732/1.3224 and i get -.36594 but how do you get the other values for a real x Ok, use your calculator. Sinx is negative in the ...
Monday, April 16, 2007 at 7:51pm

Trig
solve to four decimals places 5.0118 sinx - 3.1105=0 :for all real x values I will be happy to critique your work. Solve for sinx, then arcsinx
Monday, April 16, 2007 at 7:48pm

trig
find the exact solutions (¦È in degrees) sin^2¦È+2cos¦&Egrav​e;=-2 range= 0¡Ü¦È<360&ie​xcl;ã see the other problem, same procedure.
Monday, April 16, 2007 at 7:46pm

trig
find the exact solutions (è in degrees) sin^2è+2cosè=-2 change the sin^2 to 1-cos^2, then rearrage the equation into quadratic form, use the quadratic equaion.
Monday, April 16, 2007 at 7:44pm

Trig
Compute inverse functions to four significant digits. cos^2x=3-5cosx rewrite it as.. cos^2x + 5cosx -3=0 now you have a quadratic, solve for cos x using the equation cosx=(-5 -+ sqrt (25 +12)/2
Monday, April 16, 2007 at 7:38pm

Trig
If cosx = 10/19 an pi < x < 2pi, find the exact value of cos x/2 Use the double angle formula. Cos 2Y= sin^2 Y - cos^2Y = 1-2Cos^2 Y. let y= x/2, and 2Y=x
Saturday, April 14, 2007 at 1:58pm

Trig
Verify the identity: tanx(cos2x) = sin2x - tanx Left Side = (sinx/cosx)(2cos^2 x -1) =sinx(2cos^2 x - 1)/cosx Right Side = 2sinx cosx - sinx/cosx =(2sinxcos^2 x - sinx)/cosx =sinx(2cos^2 x -1)/cosx = L.S. Q.E.D.
Saturday, April 14, 2007 at 1:57pm

Trig
If secx = 8 and -pi/2 < x < 0, find the exact value of sin2x Use the identity sin 2x = 2(sinx)(cosx) if secx = 8, then cosx = 1/8 where x is in the fourth quadrant. consider a right angled triangle with x=1, r=8, then y=?? by Pythagoras 1^2 + y^2 = 8^2 y = -√63 (it...
Saturday, April 14, 2007 at 1:55pm

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