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April 23, 2014

Homework Help: Math: Trigonometry

Recent Homework Questions About Trigonometry

Post a New Question | Current Questions

trig
Determine whether the vectors are parallel, perpendicular or neither. 1) v = (4,1), w = (1,-4) 2) v = (2,3), w = (4,6) 3) v = (2,3), w = (3,-3) Please and thanks!
Monday, April 30, 2012 at 9:15pm

trig
Find the component form for vector v with the given amplitude and direction angle theta. |v|=20.6, theta=102.5deg
Monday, April 30, 2012 at 8:51pm

trig
tan = -10 sqrt2/ -10 sqrt 2 becomes tan=1 which is 45degree
Monday, April 30, 2012 at 8:20pm

trig
(-10√2, -10√2), find te magnitude and direction angle of the vector, measure the direction angle in [0, 360). Please help!
Monday, April 30, 2012 at 8:16pm

trig
What is 3*11+7*(-5) ?
Monday, April 30, 2012 at 6:53pm

trig
Find the dot product of u and v u= 3i+7j v= 11i-5j
Monday, April 30, 2012 at 6:42pm

trig problem
F = 1c/min = 1rev/min. = Frquency. P = 1/F = 1min/rev. = The period. T = 13:12:40 - 13:0:0 = 12min,40s. = 12 2/3 min. = 38/3 min. 1rev/min * (38/3)min = 12 2/3 rev. (2/3)rev * 360Deg/rev = 240 Deg. Ar=240-180 = 60 Deg.=Reference angle. h = hmax*sinAr = 6*sin60 = 5.2 m.
Monday, April 30, 2012 at 3:05pm

Application prob. for Trig.
Hi, A fountain in a shopping centre has a single jet of water. The height of the jet of water varies according to a sinusoidal function. A student notes that, in exactly one minute, the jet goes from a minimum height of 2m to a maximum height of 6m and back to 2m. At 13:00, ...
Monday, April 30, 2012 at 1:19pm

trig
since it's a max at t=0, that indicates a cosine function The period is 1, so we are looking at cos(2pi*t) max is 120, min is 80, so amplitude is 20, and oscillates around h=100, and our function is f(t) = 100 + 20cos(2pi*t)
Monday, April 30, 2012 at 11:54am

trig
At rest, the human heart beats once every second. At the strongest part of the beat, a person's blood pressure peaks at 120mmHg. At the most relaxed part of the beat, a person's blood pressure drops to 80mmHg. Supposing that t = 0 corresponds to the peak of the beat, ...
Monday, April 30, 2012 at 4:05am

Pre-Calc/Math
1) rewrite cosx (cosx/sinx) + sinx = csc x 2) cosx^2/sinx + sinx = csc x 3) multiply sinx by (sinx/sinx) to get same denominator this gives you cosx^2/sinx + sinx^2/sinx = cscx 4) combine your fractions (cosx^2 + sinx^2)/sinx = cscx 5) rewrite numerator 1/sinx= csc x and there...
Monday, April 30, 2012 at 1:00am

trig - incomplete
"near" doesn't mean anything. If the man is 100 ft from the tree, a 4-ft shadow means the tree is enormous. If the man is 2 ft from the tree, the tree is short.
Monday, April 30, 2012 at 12:18am

trig
a 6 foot tall man is standing near a tree on level ground .if the man shadow 4 feet long .how many feet tall is the tree?
Sunday, April 29, 2012 at 11:08pm

Trig. application
C = pi * D = 3.14 * 2*25.5 = 160.14 cm. = 1.614 m = Circumference. V = 30km/h = 30,000m / 60min=500 m/min. d = 500m/min * 4min = 2000 m. 2000m / 1.614m/rev =1239.157373 revolutions. A = 90 + 0.157373*90 = 104.2 Deg. h = 25.5 + 25.5*sin104.2 = 50.2 cm.
Sunday, April 29, 2012 at 10:29pm

Honors Trig.
Here is an easy way to do these. 1) convert all angles to 000N,090E, 180S, 270W Example: 456@29deg S of E. = 456@119 then convert to N, E coordinates. V= 456(Cos119 N + Sin119 E) Now for your problem: V= 550(cos295 N +sin295 E)+28(cos109 N+ sin109) combine N, E vector ...
Sunday, April 29, 2012 at 2:49pm

Honors Trig.
A plane is flying at a speed and direction of 550 mph, 25 degrees north of west. There is a wind of 28 mph, at an angle of 19 degrees south of the east direction. How fast is the plane actually flying? What direction is the plane traveling?
Sunday, April 29, 2012 at 2:38pm

Maths trig
Whats the workings out to get to these answers ? Jw ta
Sunday, April 29, 2012 at 12:29pm

Maths trig
Thanks :)
Sunday, April 29, 2012 at 12:27pm

Maths trig
sin2t = 2 sint cost sin3t = sint cos2t + cost sin2t (cos2t = 1 - 2sin^2 t)
Sunday, April 29, 2012 at 10:50am

Maths trig
Use compound angle formulae to express Second harmonic i2= sin2t and the the third harmonic i3=sin3t in terms of the first harmonic sint
Sunday, April 29, 2012 at 2:06am

algebra2/trig
1) looks like you are dealing with the cubes so term(n) = n^3 2) did you notice that each term is one less than a perfect square? e.g. 3 = 2^2 - 1 --term(1) 8 = 3^2 -1 -- term(2) 15 = 4^2 -1 24 = 5^2 - 1 35 = 6^2 - 1 so term(n) = (n+1)^2 -1
Saturday, April 28, 2012 at 10:43pm

algebra 2/trig
1) a (n ) = n ^ 3 1 ^ 3 = 1 2 ^ 3 = 8 3 ^ 3 = 27 4 ^ 3 = 64 5 ^ 3 = 125 6 ^ 3 = 216 2 ) a (n ) = n ^ 2 + 2 n 1 ^ 2 + 2 * 1 = 1 + 2 = 3 2 ^ 2 + 2 * 2 = 4 + 4 = 8 3 ^ 2 + 2 * 3 = 9 + 6 = 15 4 ^ 2 + 2 * 4 = 16 + 8 = 24 5 ^ 2 + 2 * 5 = 25 + 10 = 35 6 ^ 2 + 2 * 6 = 36 + 12 = 48
Saturday, April 28, 2012 at 10:31pm

TRIG
one rotation is 5π ft so the hypotenuse has length 5π and sin 15 = height/(5π) height = 5π sin 15° = ......
Saturday, April 28, 2012 at 10:12pm

algebra 2/trig
Write the next term of sequence,and then write the rule for the nth term. 1)1,8,27,64,....125 the nth is 2) 3,8,15, 24,.....35 the nth is Can you help me and correct ? thank
Saturday, April 28, 2012 at 9:16pm

TRIG
5. A wheel 5.00 ft in diameter rolls up a 15.0° incline. How far above the base of the incline is the top of the wheel after the wheel has completed one revolution? A. 4.07 ft B. 13.1 ft C. 8.13 ft D. 9.07 ft
Saturday, April 28, 2012 at 9:05pm

algebra2/trig
Write the next term of sequence,and then write the rule for the nth term. 1)1,8,27,64,....125 the nth is n 2) 3,8,15, 24,.....35 the nth is Can you help me and correct ? thank you
Saturday, April 28, 2012 at 7:55pm

trig question
Sorry, the web address is spaced out so you need to put it together..again sorry, but I really need the help. Much appreciated!
Saturday, April 28, 2012 at 6:05pm

trig question
Hi, my question is attached to the web below (picture), because I can't draw the diagram on here. Sorry for any inconvenience. Please help and thanks. imageshack . us/photo/my-images / 845 / img0043gx . jpg/
Saturday, April 28, 2012 at 6:02pm

trig question
But the question ask to find the area of AE and EB together
Saturday, April 28, 2012 at 5:55pm

trig-math
4. A carpenter wants to be sure that the corner of a building is square and measures 6.0 ft and 8.0 ft along the sides. How long should the diagonal be? A. 12 ft B. 10 ft C. 11 ft D. 14 ft 5. A wheel 5.00 ft in diameter rolls up a 15.0° incline. How far above the base of ...
Saturday, April 28, 2012 at 4:32pm

math-TRIG
i thank you for the one u did i have 40 of these i got the ans to the rest these are the one i could figure out so plz any help i acan get i thNK U a lot
Saturday, April 28, 2012 at 3:40pm

math-TRIG
1. Which angle measure is consistent with all of the following criteria? (i) The reference angle is 40°. (ii) The angle is more than one revolution. (iii) The angle's terminal side is in Quadrant II. (iv) The angle isn't positive. A. –580° B. –500°...
Saturday, April 28, 2012 at 3:33pm

trig question
sorry 1 = EO, the side along the x axis
Saturday, April 28, 2012 at 3:31pm

trig question
a 30,60 , 90 triangle has sides 1 =AO, sqrt 3 = EA and hypotenuse 2 AB = 2 sqrt 3 your angle AOB is 2*60 = 120 OE the altitude is 1 Your area = (1/2)(1)(2 sqrt 3) = sqrt 3
Saturday, April 28, 2012 at 3:30pm

trig question
NEW DIAGRAM: On a unit circle, sin x = square root 3 over 2, with center O. Vertical line from top to center of circle is PO. Horizontal line from middle to right of circle is OE. Another vertical line of AB is parallel to PO. And radius of circle (line from O to A) is 1 unit...
Saturday, April 28, 2012 at 2:57pm

trig question
On a unit circle, sin x = square root 3 over 2, with center O. Vertical line from top to center of circle is PO. Horizontal line from middle to right of circle is OE. Another vertical line of AB is parallel to PO. And radius of circle (line from O to A) is 1 unit. From A to E ...
Saturday, April 28, 2012 at 2:49pm

math-TRIG
1. Which angle measure is consistent with all of the following criteria? (i) The reference angle is 40°. (ii) The angle is more than one revolution. (iii) The angle's terminal side is in Quadrant II. (iv) The angle isn't positive. A. –580° B. –500°...
Saturday, April 28, 2012 at 1:46pm

trig problem
Hi, A fountain in a shopping centre has a single jet of water. The height of the jet of water varies according to a sinusoidal function. A student notes that, in exactly one minute, the jet goes from a minimum height of 2m to a maximum height of 6m and back to 2m. At 13:00, ...
Saturday, April 28, 2012 at 1:27pm

Trig. application
Hello.. In your previous solution to the question: "Dave is going for a ride on his unicycle. The radius of the wheel is 25.5cm. When he gets on, the valve of the wheel is at its maximum height. He pedals along a path at a speed of 30km/h. At what height will the valve be...
Saturday, April 28, 2012 at 1:21pm

Trig. application
One rotation of the wheel would cover 2(25.5)π or 51π cm 30 km/hr = 30(1000)(100) cm / 60 minutes = 50000 cm/min in 4 min Dave will have covered 4(50000) cm = 200,000 cm (using Distance = rate x time ) So the number of rotations = 200000/(51π) = 1248.274063 The ...
Saturday, April 28, 2012 at 8:51am

math - trig
Q. 1 c) -220 degrees. is -180 Plus(-40) degrees. It will be in Quadrant II Q. 2 a) 14.07 cms radius = 7.2 cm perimieter 2 x 3.14 x 7.2 = 45.216 cm angle is 112 degree 112/360x45.216 = 14.0672 or 14.07 cm Q.3 d) 21.833 50/60 is 0.833 (nearest thousandth)
Saturday, April 28, 2012 at 5:26am

math - trig
1.Which angle measure is consistent with all of the following criteria? (i) The reference angle is 40°. (ii) The angle is more than one revolution. (iii) The angle's terminal side is in Quadrant II. (iv) The angle isn't positive. A. –580° B. –500°...
Saturday, April 28, 2012 at 4:06am

Trig. application
Dave is going for a ride on his unicycle. The radius of the wheel is 25.5cm. When he gets on, the valve of the wheel is at its maximum height. He pedals along a path at a speed of 30km/h. At what height will the valve be located after he has cycled for 4 minutes? How do I find...
Saturday, April 28, 2012 at 1:01am

Trig Help!
you got it backwards π/12 = (1/2) of π/6 using cos 2A = cos^2 A - sin^2 A = 2cos^2 A - 1 so cos π/6 = 2 cos^2 π/12 - 1 √3/2 + 1 = 2cos^2 π/12 cos^2 π/12 = √3/4 + 1/2 = (√3 + 2)/4 cos π/12 = √(√3+2) /2 check: by ...
Saturday, April 28, 2012 at 12:13am

Trig Help!
Question: Trying to find cos π/12, if cos π/6 = square root 3 over 2, how to find cos π/12 using DOUBLE angle formula? This is what I got so far.. cos 2(π/6) = cos (π/6 + π/6) = (cos π/6)(cos π/6) - (sin π/6)(sin π/6) = cos^2...
Friday, April 27, 2012 at 11:59pm

Solving Trig equation
you should recognize that they are using the formula tan(A+B) = (tanA + tanB)/(1 - tanAtanB) so (tanx + tan π/3)/(1 - tanxtan(π/3) = √3 becomes tan(x+π/3) = √3 , I know tan 60° or tan 240° = √3 OR tan π/3 or tan 4π/3 = √...
Friday, April 27, 2012 at 11:56pm

Solving Trig equation
Solve the trig equation exactly in the interval 0≤x≤2π. tan x + tan π/3 ------------------ = square root 3 1 - tan x tan π/3
Friday, April 27, 2012 at 11:41pm

trig
the amplitude is 3 you can determine the max/min by simply observing the properties of the cosine curve the max of cos(anything) is 1 and its minimum is -1 so max of 4cos(.....) is s4 and its minimum is -4 so max of -3 + 4cos(....) is 1 and its min is -7
Friday, April 27, 2012 at 7:47am

trig
Consider the trigonometric function f(t) = -3+4cos(pi/3(t-3/2)) What is the amplitude/period of f(t)? What are the maximum and minimum values attained by f(t)?
Friday, April 27, 2012 at 3:28am

alg2/trig
im assuming oyu saying cos75 degree as a simple fraction; cos(75)=cos(45+30) recall the formula cos(a+b)=cos a cosb- sin a sin b cos(45+30)=cos(30)sin(45)- sin(30)sin(45) cos(45+30)=((sqrt(3))/2)((sqrt(2))/2)-&#​133; cos(45+30) =(sqrt(6)- sqrt(2))/4
Friday, April 27, 2012 at 1:05am

alg2/trig
how would you express cos(75 as a single fraction?
Thursday, April 26, 2012 at 11:11pm

Trig Question
construct a triangle in quad II with x=-4 and y = 3 since tanØ = y/x or opposite/adjacent so r^2 = (-4)^2 + 3^2 r = 5 sinx = 3/5 and cosx = -4/5 you have to know that sin 2x = 2sinxcosx = 2(3/5)(-4/5) = -24/25 cos 2x = cos^2 x - sin^2 x = 16/25 - 9/25 = 7/25 tan 2x = ...
Thursday, April 26, 2012 at 5:56pm

Trig Question
Given that tan x= -3/4 and x is in the second quadrant. Find sin 2x, cos 2x, and tan 2x (Exact, no decimals). Please show step-by-step, thank you!
Thursday, April 26, 2012 at 4:55pm

trig
I don't think the identity holds. Plug in x = pi/6. Graph (sec6x+sin2x)/(sin6x-sin2x)-tan4xcot2x and you don't get zero.
Wednesday, April 25, 2012 at 12:00pm

trig
(sec6x+sin2x)/(sin6x-sin2x)=tan4xcot2x
Wednesday, April 25, 2012 at 11:26am

trig
sin ( x ) = 5 / 12 cos ( x ) = + OR - sqrt [ 1 - sin ^ 2 ( x ) ] cos ( x ) = + OR - sqrt [ 1 - ( 5 / 1 3 ) ^ 2 ] cos ( x ) = + OR - sqrt ( 1 - 25 / 169 ) cos ( x ) = + OR - sqrt ( 169 / 169 - 25 / 169 ) cos ( x ) = + OR - sqrt ( 144 / 169 ) cos ( x ) = + OR - 12 / 13 In ...
Tuesday, April 24, 2012 at 5:13pm

trig
Prove that if Sinx=5/13 and Siny=12/13, where x and y angles in Q1, then Sin(x+y)=1
Tuesday, April 24, 2012 at 4:55pm

trig
2tanc - 3 = 3tanc - 4 -3 = tanc - 4 1 = tanc ** Plug in Graphing Calculator: arctan (1) = 45 45 + 180 = 225 Ans. : 45 and 225.
Monday, April 23, 2012 at 8:55pm

trig
Could be a dot product (scalar product) or could be a vector product (cross product) If a dot product then 6*-3 + 7*9 = 45 If a cross product then i j k 6 7 0 -3 9 0 do determinant k (6*9 -(7*-3) ) = k (54+21) = 75 in z direction
Monday, April 23, 2012 at 7:27pm

trig
find the math product of u and v u= (6,7) v= (-3,9)
Monday, April 23, 2012 at 7:19pm

trig
When does the period occur and the phase shift?
Monday, April 23, 2012 at 5:48pm

trig
150
Sunday, April 22, 2012 at 8:57pm

pre-calculus
@Adam: if these kinds of problems are hard for you to understand (i know they are for me)try algebra-dot-com. Type your question in the google custom search box. They have some problems in the archives. If they don't have the ones you're looking for, go back to the ...
Sunday, April 22, 2012 at 7:39pm

trig
when is 3 x = 2 pi ?
Sunday, April 22, 2012 at 6:03pm

trig
2sec(3x-(pi/3)) Find the period.
Sunday, April 22, 2012 at 5:56pm

Trig. - Nope
My bad. Reiny is correct. Can you see my mistake?
Saturday, April 21, 2012 at 5:39pm

Trig.
x^2-3x-28 = (x+3)(x-7) x^2-x-42 = (x+6)(x-7) x^2+10x+24 = (x+6)(x+4) x^2+x-12 = (x-3)(x+4) so, you are evaluating (x+3)(x-7)/(x+6)(x-7) - (x+6)(x+4)/(x-3)(x+4) = (x+3)/(x+6) - (x+6)/(x-3) LCD is (x+6)(x-3) [(x+3)(x-3) - (x+6)(x+6)]/(x+6)(x-3) = (x^2 - 9 - x^2 - 12x - 36)/(x+6...
Saturday, April 21, 2012 at 5:38pm

How is this trig ?? - Trig.
factor it ... (x^2-3x-28)/(x^2-x-42) -(x^2+10x+24)/(x^2+x-12) = (x-7)(x+4)/((x-7)(x+6)) - (x+6)(x+4)/((x+4)(x-3)) = (x+4)/(x+6) - (x+6)/(x-3) = [(x+4)(x-3) - (x+6)(x+6)]/((x+6)(x-3)) = ((x^2+x-12)-(x^2+12x+36)]/((x+6)(x-3)) = (-11x - 48)/(x+6)(x-3) = -(11x+48)/(x+6)(x-3)) ...
Saturday, April 21, 2012 at 5:34pm

Trig.
the way you typed it .... 0 = √20 ---> silly statement, thus no solution if you meant: 6x = √(20+6x) then square each side 36x^2 = 20+6x 36x^2 - 6x - 20 = 0 (6x - 5)(6x + 4) = 0 x = 5/6 or x = -2/3 since we squared, all answers must be verified if x = 5/6 LS = 6...
Saturday, April 21, 2012 at 5:17pm

Trig.
Are you kidding? 6 x = sqrt ( 20 ) + 6 x 6 x - 6 x = sqrt ( 20 ) 0 = sqrt ( 20 ) ???????????
Saturday, April 21, 2012 at 5:12pm

Trig ???
d(P) = -8x + 8 = 0 for a max/min of P 8x = 8 x = 1 when x = 1 P = -4+ 8+7 = 11 I will leave it up to you to interpret the answer and state the conclusion
Saturday, April 21, 2012 at 5:10pm

Trig.
Solve. Check for extraneous solution. 6x= √20+6x
Saturday, April 21, 2012 at 2:15pm

Trig
Dalco manufacturing estimate that its weakly profit, P, in hundreds of dollars,can be approximated by the formula P= -4x²+8x+7, where x is the number of units produced per week, in thousands. 1)How many units should the company produce per week to earn maximum profit 2)...
Saturday, April 21, 2012 at 1:53pm

Trig.
Subtract. Simplify is possible. (x^2-3x-28)/(x^2-x-42) -(x^2+10x+24)/(x^2+x-12)
Saturday, April 21, 2012 at 1:36pm

Trig
LS = (sin^2 t + cos^2 t)(sin^2 t - cos^2 t)/(sin^2 t cos^2 t) = 1(sin^2 t - cos^2 t)/(sin^2 t cos^2 t) = sin^2 t/(sin^2 t cos^2 t) - cos^2 t/(sin^2 t cos^2 t) = 1/cos^2 t - 1/sin^2 t = sec^2 t - csc^2 t = RS
Thursday, April 19, 2012 at 9:58pm

Trig
sin^4t-cos^4t/sin^2t cos^2t= sec^2t-csc^2t i have =(sin^2t+cos^2t)(sin^2t+cos^2t)/sin^2tco​s^2t then do i go =(sin^2t+cos^2t)/sin^2tcos^2t stumped
Thursday, April 19, 2012 at 8:26pm

algebra2/trig
4.8 hours
Thursday, April 19, 2012 at 7:36pm

Alg2/Trig
n * log ( a ) = log ( a ^ n ) log ( a ) + log ( b ) = log ( a * b ) log ( a ) - log ( b ) = log ( a / b ) 2 * log ( y ) = log ( x ^ 2 ) log( x ) + 2 * log ( y ) - log ( z ) = log ( x * y ^ 2 / z )
Thursday, April 19, 2012 at 6:34pm

Alg2/Trig
Write the log as a single function: logx + 2logy - logz
Thursday, April 19, 2012 at 6:20pm

Trig?Precalc
Do you not recognize the equation as that for a circle of radius √6 ? its center is at (0,0), so it's the most basic of any polar equation: r = 6 FYI, if you want us to show our work, show us how far you got, so we know where to concentrate the help.
Thursday, April 19, 2012 at 4:41pm

Trig/Precalc
YOu will have to use logarithms take ln of both sides ln 6 = ln (e^0.2t) ln6 = .2t lne, but lne = 1 t = ln6/.2= appr 8.959
Thursday, April 19, 2012 at 4:14pm

Trig/Precalc
solve 6=e^0.2t Round your answer to the nearest hundredth Someone please help me - I don't understand this problem at all!
Thursday, April 19, 2012 at 12:55pm

Trig?Precalc
write the rectangular equation x^2+y^2=6 in polar form. I do not want people to just post the answer! Please, show your work so that I can understand how to do these kinds of problems myself! Thank you and God Bless!
Thursday, April 19, 2012 at 12:40pm

trig
Wb = mg = 100kg * 8.8N/kg = 980 N. = Wt. of box. Fb = 980N @ 20 Deg. = Force of the box. Fp = 980*sin20 = 335.2 N. = Force parallel to ramp. Fv = 980*cos20 = 920.9 N. = Force perpendicular to ramp. Fk = Force of kinetic frictin. Fn = Fp - Fk = ma 335.2 - Fk = 100*0. 335.2 - Fk...
Wednesday, April 18, 2012 at 10:40pm

algebra-trig help asap
x= arcsec 2= arccos1/2=60deg
Wednesday, April 18, 2012 at 9:23pm

algebra-trig help asap
x=sec^-1 2 I really need help with this problem. Thanks
Wednesday, April 18, 2012 at 8:06pm

algebra-trig help asap
=tan (cos^-1(3/5) =tan(theta) =4/3
Wednesday, April 18, 2012 at 7:56pm

algebra-trig help asap
Evaluate the expression. Assume that all angles are in Quadrant I. 14. tan(arccos 3/5)
Wednesday, April 18, 2012 at 5:56pm

Trig - Please help
Can anyone help with this question? Now suppose that, starting with the first row of seats, the floor of the seating area is inclined at an angle of Theta = 25 degrees above the horizontal, and the distance that you sit up the incline is x, as shown in the fi...
Wednesday, April 18, 2012 at 5:24pm

algebra-trig help asap
by definition, arccos(4/5) is the angle whose cosine is 4/5 so, cos(that angle) is . . . 4/5!
Wednesday, April 18, 2012 at 4:44pm

algebra-trig help asap
Evaluate the expression. Assume that all angles are in quadrant 1. 1. cos(arccos4/5)
Wednesday, April 18, 2012 at 4:42pm

mth, trig
If a is in QII, sin is positive, cos is negative. 7^2 + 24^2 = 25^2, so it's a 7-24-25 triangle If b is in QIV, sin is negative, cos is positive. 5^2 + 12^2 = 13^2, so it's a 5-12-13 triangle. what did you do to find the missing sin/cos values?
Wednesday, April 18, 2012 at 4:25pm

math, trig
Graph one period of the following function. Show all work . y=2sinx+2cosx
Wednesday, April 18, 2012 at 2:13pm

mth, trig
Thanks but how did you find that? My numbers came out completely different -_-
Wednesday, April 18, 2012 at 2:05pm

mth, trig
sin a = 24/25 cos b = 5/13 now apply addition formulas
Wednesday, April 18, 2012 at 11:28am

trig
If there are h feet of tower above the man's eyes, h/65 = tan35° so, the tower height is 7 + 65tan35° = 52.5 ft
Wednesday, April 18, 2012 at 11:26am

trig
a 7 foot tall man is standing 65 feet away from a tower. if the angle of elevation is 35 degrees. what is the height of the tower to nearest tenth of a foot?
Wednesday, April 18, 2012 at 11:11am

mth, trig
Given cos a=-7/25 in quadrant II , and sin b=-12/13, in quadrant IV , find cos(a+b) and sin2a
Wednesday, April 18, 2012 at 11:10am

Trig
Can anyone help with this question. Now suppose that, starting with the first row of seats, the floor of the seating area is inclined at an angle of Theta = 25 degrees above the horizontal, and the distance that you sit up the incline is x, as shown in the fi...
Tuesday, April 17, 2012 at 4:49pm

Trig
Lisa, saw that one last night, confused about the angle 'a' in xcosa and xsina. secondly where does x come in ? describe your triangle. I have a triangle with sides a and b and Ø as its contained angle.
Tuesday, April 17, 2012 at 8:59am

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