Recent Homework Questions About Statistics
Dear PsyDAG, Thanks for your help, I suppose the answer to be 17.2 FETs?
Monday, December 2, 2013 at 7:41am
Monday, December 2, 2013 at 5:32am
Yes. 5% of 300 = 15
Sunday, December 1, 2013 at 10:21pm
1. D Chi Square distributions are positively skewed (skewed to the right). As the degrees of freedom increases, the Chi Square distribution will approach a normal symmetrical distribution. Smaller degrees of freedom will skew more to the right. 2. A Ho: The variables are ...
Sunday, December 1, 2013 at 8:14pm
We have a population of all adult women. We take a random sample from this population and create a confidence interval. If we take many, many, many different samples from this population we will obtain many, many, many different sample means and confidence intervals created ...
Sunday, December 1, 2013 at 8:09pm
If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events. 13/52 * 12/51 * 11/50 * 10/49 * (13*3)/48 = ?
Sunday, December 1, 2013 at 4:26pm
Please only post your questions once. Repeating posts will not get a quicker response. In addition, it wastes our time looking over reposts that have already been answered in another post. Thank you. A
Sunday, December 1, 2013 at 2:05pm
(10+3 +4+ 25 + 1+4+ 4 + 12+ 6 +8 +10)/11 87/11 = 7.9 Answer B
Sunday, December 1, 2013 at 2:03pm
There are different ways you can do this kind of problem, but the formula below might be one of the easier ways: s/[1 + (1.645/√2n)] ..to.. s/[1 - (1.645/√2n)] ...where s = standard deviation, 1.645 represents the 90% confidence interval using a z-table, and n = ...
Saturday, November 30, 2013 at 7:44pm
whether it is one-tailed or two tailed? and if one tailed...I do agree with you now that this is the left tail test. However I am not sure how to handle negative value on t. Here is what I did. I used formula for hypothesis test with mu unknow, t=(xbar-mu)/(sd/sqr n)=(26-25.02...
Saturday, November 30, 2013 at 12:27pm
Using the telephone numbers listed in your local directory as your population, randomly obtain 20 samples of size 3. From each telephone number identified as a source, take the fourth, fifth, and sixth digits. a. Calculate the mean of the 20 samples b. Draw a histogram showing...
Sunday, June 30, 2013 at 7:58pm
Mean=9 Variance=792 Standard Deviation=28.14
Monday, May 16, 2011 at 5:20pm