Thursday

April 17, 2014

April 17, 2014

**Recent Homework Questions About Statistics**

Post a New Question | Current Questions

**Statistics **

A random sample of 150 towns in a western state had a mean annual precipitation of 2.86 inches. Assume that the population standard deviation is known to be 0.78 inches. Compute the 95% confidence interval for μ.
*Wednesday, March 19, 2014 at 2:45am*

**statistics**

2
*Wednesday, March 19, 2014 at 2:40am*

**statistics**

d
*Wednesday, March 19, 2014 at 12:42am*

**statistics**

Find the critical value for the hypothesis test, given the following. (Give your answer correct to two decimal places.) Ha: ó1 > ó2, with n1 = 7, n2 = 16, and á = 0.05 F=?
*Tuesday, March 18, 2014 at 8:19pm*

**statistics**

In a survey of families in which both parents work, one of the questions asked was, "Have you refused a job, promotion, or transfer because it would mean less time with your family?" A total of 200 men and 200 women were asked this question. "Yes" was the ...
*Tuesday, March 18, 2014 at 8:18pm*

**statistics**

Find the value of z that would be used to test the difference between the proportions, given the following. (Use G - H. Give your answer correct to two decimal places.) Sample n x G n=384 x=314 H n=423 x=329
*Tuesday, March 18, 2014 at 7:45pm*

**statistics**

Use a confidence interval formula for proportions. CI99 = p + or - (2.58)(√pq/n) ...where √ = square root, p = x/n, q = 1 - p, and n = sample size. Hint: x = 300, n = 375 I hope this will help get you started.
*Tuesday, March 18, 2014 at 5:05pm*

**statistics**

Use a binomial probability formula or use a binomial probability table. Formula: P(x) = (nCx)(p^x)[q^(n-x)] For a): Find P(0) for none For b): Take 1 - P(0) for at least 1 For c): Find P(6) for all If you use the table, p = .04, n = 6 (sample size), x = the values needed for a...
*Tuesday, March 18, 2014 at 4:59pm*

**Statistics**

Formula to find sample size: n = [(z-value)^2 * p * q]/E^2 ... where n = sample size, z-value is found using a z-table for 95% confidence, p = .5 (when no value is stated in the problem), q = 1 - p, ^2 means squared, * means to multiply, and E = .04 (4% in the problem). Plug ...
*Tuesday, March 18, 2014 at 4:51pm*

**statistics**

Smith is a weld inspector at a shipyard. He knows from keeping track of good and substandard welds that for the afternoon shift 5% of all welds done will be substandard. If Smith checks 300 of the 7500 welds completed that shift, what is the probability that he will find ...
*Tuesday, March 18, 2014 at 4:35pm*

**statistics**

THE FIRST STUDENT
*Tuesday, March 18, 2014 at 4:23pm*

**statistics**

n
*Tuesday, March 18, 2014 at 4:13pm*

**statistics**

You have an SRS of 15 observations from a Normally distributed population. What critical value would you use to obtain a 98% confidence interval for the mean μ of the population? I know the answer is 2.602...but I do not understand why Tell me if I'm wrong: n=15 ...
*Tuesday, March 18, 2014 at 1:34pm*

**STATISTICS**

h
*Monday, March 17, 2014 at 9:53pm*

**statistics**

C
*Monday, March 17, 2014 at 9:28pm*

**help ms sue lang arts**

For Questions 1–6, read the play excerpt below and answer the questions that follow. Jaws of the Water ACT TWO At rise we see DAD, TINA, and MARK rushing in and out of the living room. Each enters carrying important items—such as sleeping bags, rain gear, and ...
*Monday, March 17, 2014 at 7:04pm*

**Statistics**

Determine the minimum sample size required in order to be 95% confident that our estimate is within 4% of the true percent of all US households using e-mail. Assume no prior estimate available.
*Monday, March 17, 2014 at 7:01pm*

**statistics**

a resturant must choose 5 employees from 12 applicants. in how many ways can they do that?
*Monday, March 17, 2014 at 5:43pm*

**statistics**

a machine has 0.04 probability of producing a defective item. If it produces 6 items find: a. probability none is defective b. at least one is defective c. all are defective
*Monday, March 17, 2014 at 5:41pm*

**statistics**

I assume you want two answers,since "all are correct and at least one is wrong" is impossible. P(all correct) = 1/4^6 P(some wrong) = 1 - P(all correct)
*Monday, March 17, 2014 at 5:36pm*

**statistics**

80%
*Monday, March 17, 2014 at 4:57pm*

**statistics**

a quiz had 6 questions, each with 4 possible answers (only one of which is correct). If you answer them at random, find the probability that all are correct and at least one is wrong.
*Monday, March 17, 2014 at 3:12pm*

**statistics**

A clinical trial test a method designed to increase probability of conceiving a girl.In study 375 were born and 300 were girls Use sample data to construct 99%confidence interval of percentage girls born
*Monday, March 17, 2014 at 12:28pm*

**stat**

I don't know what your "rule of thumb" is, but: a. 95% = mean ± 1.96 SD b. Z = (score-mean)/SD Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to ...
*Monday, March 17, 2014 at 10:42am*

**Statistics**

A standard pack of 52 cards consists of 4 suits, hearts, diamonds, clubs and spades. Each suit has 13 cards, from Ace to King. We deal randomly 5 cards from the deck of 52. 2 deals differing only by the order are considered the same. How many different deals are there? How ...
*Monday, March 17, 2014 at 3:35am*

**statistics**

(7.73/SQRT (24) = 1.577879643, next we subtract the data value (70) from the mean (73) as follows (70 – 73 = -3); the values of the two equations are divided as follows (-3/1.577879643 = 1.901285699).
*Sunday, March 16, 2014 at 8:47pm*

**statistics**

95% = mean ± 1.96 SEm SEm = SD/√n
*Sunday, March 16, 2014 at 8:31pm*

**Statistics (?)**

No data given. Z = (mean1 - mean2)/standard error (SE) of difference between means SEdiff = √(SEmean1^2 + SEmean2^2) SEm = SD/√n If only one SD is provided, you can use just that to determine SEdiff. Find table in the back of your statistics text labeled something ...
*Sunday, March 16, 2014 at 8:30pm*

**Math (Partial)**

First two questions and last. Z = (score-mean)/SD SD^2 = variance Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability of the Z score.
*Sunday, March 16, 2014 at 8:27pm*

**statistics**

85%
*Sunday, March 16, 2014 at 8:11pm*

**Statistics**

Assuming there is no advance procurement and that this is NOT a multiyear contract, what is the correct amount to includes in your budget request for FY04 and FY05 for this contract?
*Sunday, March 16, 2014 at 7:13pm*

**Business Statistics**

a sample of 16 people reveals the mean consumption to be 60 gallons with the standard of deviation of 20 gallons
*Sunday, March 16, 2014 at 2:47pm*

**Statistics**

Compare the standard deviation for the heights of males and the standard deviation for the heights of females in the class.
*Sunday, March 16, 2014 at 1:18am*

**statistics**

A food manufacturer samples 7 bags of pretzels off the assembly line and weighs their contents. If the sample mean is 14.2 oz and the sample standard deviation is 0.60 oz., find the 95% confidence interval of the true mean.
*Sunday, March 16, 2014 at 1:00am*

**statistics**

Events A, B, C are define as sample space S. Their corresponding sets of sample points do not intersect, and their union is S. Furthermore, event b is twice as likely to occur as event A, and event C is twice as likely to occur as event B. Determine the probability of each of ...
*Saturday, March 15, 2014 at 5:43am*

**statistics**

Canadians are becoming more conscious of the importance of good nutrition, and some researchers believe that we may be altering our diets to include less red meat and more fruits and vegetables. To test this theory, a researcher decides to select hospital nutritional records ...
*Saturday, March 15, 2014 at 3:14am*

**statistics**

round 1.394 to nearest hundred
*Friday, March 14, 2014 at 3:25pm*

**statistics**

two students recently took a statistics for the behavorial test . the students are at different schools but wanted to compare their performance. The first student scored 80 on the test. Her class average was 50 with a standard deviation of 10. Which student did better?
*Friday, March 14, 2014 at 12:30pm*

**statistics**

Which two scales of measurement always require nonparametric procedures and why?
*Friday, March 14, 2014 at 2:50am*

**Statistics**

.967
*Thursday, March 13, 2014 at 9:36pm*

**Statistics Question (Confidence Interval)**

h
*Wednesday, March 12, 2014 at 4:35pm*

**Statistics**

!@#$%^&
*Wednesday, March 12, 2014 at 3:57pm*

**probability and statistics**

a multiple choice test onsists of 8 questions, each with 4 possible answers but only one of which is correct.what is the probability that an unprepared student will, by chance, get, a. all correct answers, b. exactly 5 correct answers, c. at most 4 correct answers, d. at most ...
*Wednesday, March 12, 2014 at 5:04am*

**Statistics**

Looks like you might be filling in a table for a one-way ANOVA test. Your ANOVA summary table has the following setup: Source.....SS.....df.....MS.....F Between Within Totals Here are a few hints: SS total = SS between + SS within To calculate df between: k - 1 Note: k = ...
*Tuesday, March 11, 2014 at 5:00pm*

**6th grade math - statistics**

The middle 50% would be from between 3 and 4 to between 8 and 10 (the middle 6 scores). Q1 defines the lowest 25% (0, 1, 3), while Q3 defines the highest 25% (10, 12, 12).
*Tuesday, March 11, 2014 at 2:44pm*

**statistics**

Answer is 10, I cannot provide an explanation but it was an answer on one of my assignments.
*Tuesday, March 11, 2014 at 2:38pm*

**Statistics**

An industrial engineer has found that the standard household light bulbs produced by a certain manufacturer have a useful life that is normally distributed with a mean of 250 hours and a variance of 2500. (a) What is the probability that a randomly selected bulb from this ...
*Tuesday, March 11, 2014 at 10:09am*

**Elementary Statistics**

5*4*3= 60
*Monday, March 10, 2014 at 7:05pm*

**6th grade math - statistics**

Can you explain why Q1 = 3.5 and Q3 is 9 out of this dataset 0, 1, 3, 4, 6, 7, 7, 7, 8, 10, 12, 12. My answers were: Assuming median would be 7 (using numbers in positions 6 and 7 where 7+7/2 = 7) Q1 dataset would be 0,1,3,4,6; Q1 = 3 Q2 dataset would be 7,8,10,12,12; Q3= 10 ...
*Monday, March 10, 2014 at 5:17pm*

**Statistics**

The mean serves as a fulcrum or balance point for a distribution. Therefore the difference from 30 must be the same on both sides. A wide variation of values could fit both situations. However, in the second situation, all scores could be 30.
*Monday, March 10, 2014 at 3:11pm*

**Statistics**

Is that value the Z score or the probability? Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability (.095) and its Z score.
*Monday, March 10, 2014 at 3:00pm*

**statistics**

I'm not sure what you might be asking. Z = (score-mean)/SD Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.
*Monday, March 10, 2014 at 2:55pm*

**Statistics**

In an experiment, you measure the popularity of two brands of soft drinks (factor A), and for each brand you test males and females (factor B). The following table shows the main effect and cell means from the study: Factor A Level A1: Level A2: Brand X Brand Y Level B1: 14 23...
*Monday, March 10, 2014 at 1:03pm*

**Statistics**

A researcher investigated the effect of volume of background noise on participants’accuracy rates while performing a difficult task. He tested three groups of randomly selected students and obtained the following means and sums of squares: Volume Source Sum of sqs. df ...
*Monday, March 10, 2014 at 11:13am*

**statistics**

assuming that adults have IQ scores that are normally distributed with a mean of 100 and standard deviation of 15. Find the probability that a randomly selected adult has an IQ less than 121.
*Monday, March 10, 2014 at 10:22am*

**statistics**

1. A company decides to add a new program that prepares randomly selected sales personnel to increase their number of sales per month. The mean number of sales per month for the overall population of sales people at this national company is 25 with a standard deviation of 4. ...
*Monday, March 10, 2014 at 1:04am*

**Statistics**

What is 0.095 on the z-score table or where
*Sunday, March 9, 2014 at 8:59pm*

**statistics**

You can plug in your data and play around with it at http://davidmlane.com/hyperstat/z_table.html
*Sunday, March 9, 2014 at 7:12pm*

**statistics**

Assuming that the distribution is normal for weight relative to the ideal and 99% of the male participants scored between (–53.68, 64.64), where did 95% of the values for weight relative to the ideal lie? R
*Sunday, March 9, 2014 at 4:22pm*

**Statistics**

Put in Binomial Probability Formula? probability ( 2 of 22 are lost) = C(22,2) (1/200)^2 (199/200)^20
*Sunday, March 9, 2014 at 6:59am*

**Statistics**

List five numbers for which the sample mean is 30 and not all numbers are equal and would have a mean of 30 but all numbers are equal
*Sunday, March 9, 2014 at 3:24am*

**Statistics**

How do I plug this into the Binomial Probability Formula? prob(lost) = 5/1000 = 1/200 prob(not lost) = 199/200 prob( 2 of 22 are lost) = C(22,2) (1/200)^2 (199/200)^20 = .005224..
*Sunday, March 9, 2014 at 12:45am*

**Statistics**

Prev Up Next (1 pt) Suppose that in the year 2000, the cost of a compact car averaged $ 12600 and that in 2003, the cost averaged $ 14100. Assuming that the relationship between year t and cost c is linear, develop a formula for predicting the average cost of a compact car in ...
*Saturday, March 8, 2014 at 5:14pm*

**Statistics**

Please only post your questions once. Repeating posts will not get a quicker response. In addition, it wastes our time looking over reposts that have already been answered in another post. Thank you.
*Saturday, March 8, 2014 at 12:58pm*

**Statistics**

Z = (score-mean)/SD Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score. OR… http://davidmlane.com/hyperstat/z_table.html
*Saturday, March 8, 2014 at 12:56pm*

**Statistics**

If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events. 3/8 * 3/8 = ? 3/8 * (3-1)/(8-1) = ?
*Saturday, March 8, 2014 at 12:55pm*

**Statistics**

I have 8 marbles: 3 blue, 1 green, 4v reds. What is the probability of selecting a blue marble twice with replacement and twice without replacement
*Saturday, March 8, 2014 at 12:09pm*

**Statistics**

For the z-score mean-SD how do you get the percentage without using a calculator
*Saturday, March 8, 2014 at 11:22am*

**Statistics**

I thought I had given you the answer. finding the z-score results in a mean of 0 and a standard deviation of 1 so in the link I gave you .... http://davidmlane.com/hyperstat/z_table.html enter 0 for the mean 1 for the sd click on "below" and enter -.75 click ...
*Saturday, March 8, 2014 at 10:32am*

**Statistics**

If I don't know the mean and the standard deviation how can I find the area of z-score -0.75
*Saturday, March 8, 2014 at 10:28am*

**Statistics**

If I don't know the mean and the standard deviation how can I find the area of z-score -0.75
*Saturday, March 8, 2014 at 9:06am*

**Statistics**

Fun to play around with this excellent site http://davidmlane.com/hyperstat/z_table.html
*Saturday, March 8, 2014 at 8:41am*

**Statistics **

Consider the standard normal distribution. Find the area for the z-score -0.75. Draw a picture of this distribution showing the location of the z-score and the mean. Shade the region corresponding to the area found for the z-score.
*Saturday, March 8, 2014 at 8:37am*

**Statistics**

Use David's excellent "normal distribution" calculator http://davidmlane.com/hyperstat/z_table.html click on "area from a value" enter the data, click on "between" and enter 8 and 11 to get .4467 You can enter the data directly, no need...
*Saturday, March 8, 2014 at 7:53am*

**Statistics**

In a certain population of clover, the number of flowers on each plant is approximately normally distributed with a mean of 10.8 flowers/plant and a standard deviation of 2.1 flowers/plant. What percentage of the plants fall between 8 and 11 flowers?
*Saturday, March 8, 2014 at 7:09am*

**statistics**

In a random sample of 100 customers, 62 returned with a month. For a 95% confidence interval on the proportion of customers who return for an oil change, the lower limit is:
*Friday, March 7, 2014 at 11:21pm*

**Statistics**

393
*Friday, March 7, 2014 at 7:36pm*

**Statistics**

If the experiment involves two independent variables, the possibility of an interaction between the variables can be measured.
*Friday, March 7, 2014 at 4:07pm*

**Statistics**

Help please... What are some reason for conducting an experiment with two factors?
*Friday, March 7, 2014 at 3:16pm*

**statistics**

a large shipment of computer chips, of which 5% are actually defective, a quality control manager decides to test chips until he finds the first defective. What is the probability that the manager finds the first defective chip on the first test? in Homework Help
*Friday, March 7, 2014 at 4:04am*

**statistics**

.5
*Thursday, March 6, 2014 at 10:10pm*

**Statistics**

Pick any person. There are 16 people to shake hands with. Since there are 18 people, there are 18*16 shakes. But, counting this way, each shake is counted twice, once for each person. So, the final answer is 18*16/2
*Thursday, March 6, 2014 at 12:05pm*

**statistics**

ky
*Thursday, March 6, 2014 at 11:27am*

**Statistics**

If the king and queen invite 8 knights and thier wives then how many handshakes will there be if each couple cannot handshake with their lifetime partner. (I think this involves the king and queen as a couple).
*Thursday, March 6, 2014 at 9:55am*

**Statistics**

30
*Wednesday, March 5, 2014 at 9:09pm*

**statistics**

.05,.07
*Wednesday, March 5, 2014 at 5:23pm*

**statistics**

Please only post your questions once. Repeating posts will not get a quicker response. In addition, it wastes our time looking over reposts that have already been answered in another post. Thank you.
*Wednesday, March 5, 2014 at 2:25pm*

**statistics (?) **

What null hypothesis do you want to consider?
*Wednesday, March 5, 2014 at 2:24pm*

**statistics**

Post a null hypothesis that would use a t test statistical analysis.. Use the same hypothetical situation taken in the t test hypothesis, and turn it into a null hypothesis using a one-way ANOVA analysis and a two-way ANOVA.
*Wednesday, March 5, 2014 at 11:49am*

**statistics**

A telephone company's records indicate that private customers pay on average $17.10 per month for long-distance telephone calls. A random sample of 10 customers' bills during a given month produced a sample mean of $22.10 expended for long-distance calls and a sample ...
*Wednesday, March 5, 2014 at 11:45am*

**statistics**

Post a null hypothesis that would use a t test statistical analysis.. Use the same hypothetical situation taken in the t test hypothesis, and turn it into a null hypothesis using a one-way ANOVA analysis and a two-way ANOVA.
*Wednesday, March 5, 2014 at 11:22am*

**probability and statistics**

4
*Tuesday, March 4, 2014 at 10:14pm*

**statistics**

2
*Tuesday, March 4, 2014 at 9:06pm*

**math probability**

Z = (score-mean)/SD Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.
*Tuesday, March 4, 2014 at 4:19pm*

**statistics**

Conduct an ANOVA comparing participants recall will vary as a function of stress levels. Conduct an ANOVA comparing participants recall at Time 1 across all three stress level conditions (low, medium,and high). Conduct post hoc tests if needed, using the Tukey method.
*Monday, March 3, 2014 at 8:12pm*

**statistics**

Poisson distribution (m = mean): P(x) = e^(-m) m^x / x! Values: x = 3 m = 5 Substitute and calculate.
*Monday, March 3, 2014 at 5:25pm*

**statistics**

Looks like you might be doing a one-way ANOVA test for the data you choose for this project. Your ANOVA summary table should have the following setup: Source.....SS.....df.....MS.....F Between Within Totals If you calculate by hand, here are a few hints: SS total = SS between...
*Monday, March 3, 2014 at 5:18pm*

**statistics**

Conduct an ANOVA comparing participants recall will vary as a function of stress levels. Conduct an ANOVA comparing participants recall at Time 1 across all three stress level conditions (low, medium, and high). Coduct post hoc tests if needed, using the Tukey method.Write a ...
*Monday, March 3, 2014 at 3:31pm*

**Statistics**

@John I have come from a year later to reply to your concern, to uproot this tyranny that is Math Guru. No longer shall we sit wondering what the other half of the question is. No longer must we be given a formula and have to solve it out. NO LONGER MUST WE SIT THROUGH THIS. ...
*Monday, March 3, 2014 at 2:53pm*

**Statistics**

I got only love for John. The answer is fate
*Monday, March 3, 2014 at 2:46pm*

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