Calculate the concentration of the initial nitrate stock solution (in ppm) if exactly 0.361 g of
KNO3 is dissolved in a 1 L volumetric flask with distilled water.
I assume you mean ppmw (ppm by mass and not by volume)
So mass H2O in that 1 L is 1000 g and that added to the 0.361 gives you a mass of solution of 1000.361g.
0.361g x (1E6/1000.361) = ? ppmw and you round that off to three significant figures and you get the same answer as if were calculated as ppmv.
1 ppm = 1 mg/L
0.361 g = 361 mg, so 361 ppmv
To calculate the concentration of the initial nitrate stock solution in parts per million (ppm), we need to know the amount of the solute (KNO3) dissolved in the solution and the volume of the solution.
In this case, we have 0.361 g of KNO3 dissolved in a 1 L volumetric flask.
To calculate the concentration in ppm, we use the following formula:
Concentration (ppm) = (Mass of solute / Volume of solution) x 10^6
Plugging in the given values:
Concentration (ppm) = (0.361 g / 1 L) x 10^6
Simplifying the equation:
Concentration (ppm) = 361,000 ppm
Therefore, the concentration of the initial nitrate stock solution is 361,000 ppm.