Two collinear points are given in the table, give a third point that is also on this line x 0 4. It is written vertically on a graph, the other side states y 0 -3.
I do not understand how to find the third point for each problem. I missed this lesson, can you tell me how to solve this to get the answer?
well, for each increase of 4 in x, y goes down by 3
y=-3x/4
another point, let x=20, then y=-15
A square is cut in half on the diagonal, creating two equal triangles.each triangle has an area of 0.32 square units. What is the lenth, in units, of the original square. HELP ME PLEASEE
To find the third point on the line, we can use the slope-intercept form of a linear equation, which is given by: y = mx + b. Here, 'm' represents the slope of the line and 'b' represents the y-intercept.
To determine the slope of the line, we take the difference in y-coordinates divided by the difference in x-coordinates between the two given points. In this case, the two given points are (0,0) and (4,-3).
Difference in y-coordinates = -3 - 0 = -3
Difference in x-coordinates = 4 - 0 = 4
Slope (m) = (-3) / 4 = -3/4
Now, let's find the y-intercept (b) by substituting one of the given points into the slope-intercept form equation. We can use the point (0,0) as it seems to be one of the given points.
0 = (-3/4)(0) + b
0 = b
So, the equation of the line is y = (-3/4)x.
To find the third point, we need to substitute a value of x into this equation and solve for y. Let's substitute x = 8 into the equation:
y = (-3/4)(8)
y = -6
So, the third point on the line is (8,-6).
To find a third point that is collinear with the given two points (x,0) and (y,-3), where x=0 and y=4, you can use the fact that collinear points lie on the same straight line.
First, let's plot the two given points on a graph.
The first point is (x,0) = (0,0), and the second point is (y,-3) = (4,-3).
Now, draw a straight line passing through these two points.
To find a third point that lies on this line, you can choose any x-coordinate value and find the corresponding y-coordinate value using the equation of the line.
The equation of a straight line passing through two points (x1, y1) and (x2, y2) can be written as:
y - y1 = (y2 - y1) / (x2 - x1) * (x - x1)
Let's substitute the values for the first point (0,0) and the second point (4,-3) into the equation:
y - 0 = (-3 - 0) / (4 - 0) * (x - 0)
Simplifying this equation gives:
y = -3/4 * x
Now, you can choose any value for x, and by substituting it into the equation, you can find the corresponding value for y.
For example, let's choose x = 2:
y = -3/4 * 2 = -3/2 = -1.5
So, the third point on the line is (2, -1.5).
By following this process, you can find any additional points that lie on the same line.