Divide 120 into two parts so that thrice the smaller one is equal to twice the larger one
just translate to Math
let the smaller be x
let the larger by y
clearly : x+y 120
"that thrice the smaller one is equal to twice the larger one"
---> 3x = 2y
from the first:
y = 120-x
into the 2nd:
3x = 2(120-x)
3x = 240 - 2x
5x = 240
x = 48
smaller is 48, the larger is 72
OR
from "that thrice the smaller one is equal to twice the larger one" , we can see that they would be in the ratio of 2:3 or 2a:3a
2a+3a=120
a = 24
so 2a is 48
and 3a is 72
Ya question ap na kaisa kiya ha
Ye 72 kha sy aya h
I dont even understand the answer...
To solve this problem, let's represent the two parts as variables.
Let's assume the smaller part is 'x'.
So, the larger part would be '120 - x' (since we are dividing 120 into two parts).
According to the given condition, thrice the smaller part is equal to twice the larger part, which can be written as:
3x = 2(120 - x)
Now, let's solve this equation to determine the values of 'x'.
Expanding the equation:
3x = 240 - 2x
Combining like terms:
3x + 2x = 240
5x = 240
Dividing both sides of the equation by 5:
x = 48
So, the smaller part is 48, and the larger part is:
120 - x = 120 - 48 = 72
Therefore, dividing 120 into two parts such that thrice the smaller part is equal to twice the larger part, the smaller part is 48 and the larger part is 72.