which gas sample has the greatest volume at STP?
a)10.0g Ar
b)10.0g Kr
c) 10.0 g Xe
d) none of the above (They all have the same number)
Ar
To determine which gas sample has the greatest volume at STP (Standard Temperature and Pressure), we need to compare the number of moles of each gas sample.
To find the number of moles, we can use the formula:
Number of moles = mass / molar mass
The molar mass of each gas can be found from the periodic table.
Ar (Argon): 39.95 g/mol
Kr (Krypton): 83.8 g/mol
Xe (Xenon): 131.3 g/mol
Let's calculate the number of moles for each gas sample:
a) Ar (Argon):
Number of moles = 10.0 g / 39.95 g/mol = 0.250 moles
b) Kr (Krypton):
Number of moles = 10.0 g / 83.8 g/mol = 0.119 moles
c) Xe (Xenon):
Number of moles = 10.0 g / 131.3 g/mol = 0.076 moles
Comparing the number of moles, we can see that Ar (Argon) has the greatest number of moles (0.250 moles). Therefore, the gas sample with the greatest volume at STP is Ar (Argon).
So the correct answer is:
a) 10.0g Ar
To determine which gas sample has the greatest volume at STP (Standard Temperature and Pressure), we need to compare the molar masses of the given gases and consider Avogadro's law.
First, let's calculate the number of moles for each gas sample by dividing the given mass by the molar mass of each gas:
a) Molar mass of Ar = 39.95 g/mol
Moles of Ar = mass of Ar / molar mass of Ar
= 10.0 g / 39.95 g/mol
b) Molar mass of Kr = 83.80 g/mol
Moles of Kr = mass of Kr / molar mass of Kr
= 10.0 g / 83.80 g/mol
c) Molar mass of Xe = 131.29 g/mol
Moles of Xe = mass of Xe / molar mass of Xe
= 10.0 g / 131.29 g/mol
Next, according to Avogadro's law, one mole of any gas at STP occupies the same volume (22.4 liters). Therefore, the amount of gas, measured in moles, directly determines the volume at STP.
Now, let's calculate the volume for each gas sample:
a) Volume of Ar = Moles of Ar * 22.4 liters/mol
= (10.0 g / 39.95 g/mol) * 22.4 liters/mol
b) Volume of Kr = Moles of Kr * 22.4 liters/mol
= (10.0 g / 83.80 g/mol) * 22.4 liters/mol
c) Volume of Xe = Moles of Xe * 22.4 liters/mol
= (10.0 g / 131.29 g/mol) * 22.4 liters/mol
Finally, by comparing the volumes calculated for each gas sample, you can determine which gas has the greatest volume at STP.