Is 4786 Jules of heat are transferred to 89 g sample of an unknown material within the initial temperature of 23°C what is the specific heat of the material if the final temperature is 89.5 ° C
See your previous posts. Same formula, different numbers and different unknown.
To find the specific heat of the material, we can use the formula:
Q = m * c * ΔT
Where:
Q is the amount of heat transferred
m is the mass of the sample
c is the specific heat of the material
ΔT is the change in temperature
In this case, we have the following values:
Q = 4786 J
m = 89 g
ΔT = 89.5 °C - 23 °C = 66.5 °C
Substituting these values into the formula, we have:
4786 J = 89 g * c * 66.5 °C
To find the value of c, we can rearrange the equation:
c = 4786 J / (89 g * 66.5 °C)
Calculating this, we find:
c ≈ 0.829 J/g°C
Therefore, the specific heat of the material is approximately 0.829 J/g°C.