Building a rectangular sandbox for younger brother. The length. Is 1 foot longer than twice the width of the sandbox. The perimeter of the sandbox is 29 feet what equation could be used to determine the w, the width, in feet, of the sandbox?

width -- x

length -- 2x+1

x+x + 2x+1 + 2x+1 = 29
6x+2=29

take over

Just realized I used x instead of w, no big deal.

To determine the equation for finding the width of the sandbox, let's break down the given information:

1. The length of the sandbox is 1 foot longer than twice the width.
2. The perimeter of the sandbox is 29 feet.

Let's represent the width of the sandbox as "w" (in feet).

According to the first point, the length of the sandbox is 1 foot longer than twice the width. So, the length can be expressed as (2w + 1) feet.

The perimeter of any rectangle can be calculated by adding the lengths of all four sides. In this case, the perimeter is given as 29 feet. So, the equation can be formed as:

Perimeter = 2 × (length + width)

29 = 2 × ((2w + 1) + w)

Now, we can simplify and solve this equation to find the width of the sandbox (w).

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