Use the following values for the arrows in the drawing: a = 185 J of heat; b = 45 J of heat; c = 115 J of work; d = 40 J of work; e = 65 J of work; and f = 190 J of heat. Find the change in the internal energy of object A only.

Use the First Law of Thermodynamics Be careful with sign conventions.
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Find the change in the internal energy of object B only.
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Find the change in the internal energy for objects A and B together.
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I have no idea what this looks like.

Use dE = q + w
q will be joules of heat. If the arrow goes INTO the object it is +, if OUT OF the object it is -.

Same sign convention for work. If the arrow goes INTO the object it is +w; if out of the object it is -w.

To find the change in internal energy of object A, we can use the First Law of Thermodynamics, which states that the change in internal energy of an object is equal to the heat added to the system minus the work done by the system.

Let's analyze the given values for each arrow in the drawing:

- Arrow a represents 185 J of heat added to object A.
- Arrow b represents 45 J of heat added to object B.
- Arrow c represents 115 J of work done by object A.
- Arrow d represents 40 J of work done on object B.
- Arrow e represents 65 J of work done on object B.
- Arrow f represents 190 J of heat added to object A.

Now, let's calculate the change in internal energy of object A.

The heat added to object A is 185 J (arrow a), and the work done by object A is 115 J (arrow c). However, we need to be careful with sign conventions.

According to the First Law of Thermodynamics, the heat added to the system is positive, and the work done by the system is negative.

So, the heat added to object A is +185 J, and the work done by object A is -115 J.

Now, let's calculate the change in internal energy of object A:

Change in Internal Energy of Object A = Heat added to object A - Work done by object A
= +185 J - (-115 J)
= +185 J + 115 J
= 300 J

Therefore, the change in internal energy of object A is 300 J.

To find the change in internal energy of object B, we can follow the same approach:

The heat added to object B is 45 J (arrow b), and the work done on object B is 40 J (arrow d) and 65 J (arrow e).

Again, using sign conventions, the heat added to object B is +45 J, and the work done on object B is -40 J and -65 J.

Change in Internal Energy of Object B = Heat added to object B - Work done on object B
= +45 J - (-40 J) - (-65 J)
= +45 J + 40 J + 65 J
= 150 J

Therefore, the change in internal energy of object B is 150 J.

To find the change in internal energy for objects A and B together, we can simply add the changes in internal energy of each object:

Change in Internal Energy for Objects A and B together = Change in Internal Energy of Object A + Change in Internal Energy of Object B
= 300 J + 150 J
= 450 J

Therefore, the change in internal energy for objects A and B together is 450 J.