At some temperature, the reaction
PCl3(g)+Cl2(g)====PCl5(g)
is at equilibrium when the concentration of PCl3, Cl2, and PCl5 are 10, 9.0, and 12 mol/L,
respectively. Calculate the value of Kc for this reaction at that temperature.
It is given that the reaction at the given temperature is in equilibrium.
Next check if the reaction is homogeneous: all gases, so homogeneous.
Now denote the stoichiometric coefficients by a,b and c for the reactants and products respectively (all equal to 1 in this case).
then Kc is given by:
Kc=[PCl5]^c/([PCl3]^a [Cl2]^b)
[] means concentration (mol/L).
Note that the coefficients in this equation are a, b, and c, and those have a value of 1 in this instance.
thanks =)
To calculate the value of Kc for the given reaction at the given temperature, we need to use the concentrations of the reactants and products and plug them into the equilibrium expression.
The equilibrium expression for the reaction is:
Kc = [PCl5] / ([PCl3] * [Cl2])
Where [PCl5], [PCl3], and [Cl2] represent the concentrations of PCl5, PCl3, and Cl2, respectively.
Given that the concentrations of PCl5, PCl3, and Cl2 are 12 mol/L, 10 mol/L, and 9.0 mol/L, respectively, we can substitute these values into the equilibrium expression:
Kc = (12) / (10 * 9.0)
Kc = 1.3333
Therefore, the value of Kc for this reaction at the given temperature is approximately 1.3333.