Calculating Kc

Welcome to the "Calculating Kc" category on Questions LLC! Whether you're a chemistry enthusiast or a student looking for help with your homework, you've come to the right place. This category is dedicated to answering all your queries related to calculating the equilibrium constant, Kc. From understanding the concept of Kc to solving numerical problems, our community of experts is here to provide you with clear explanations and step-by-step solutions. So, explore the questions in this category, ask your own, and let's unravel the fascinating world of equilibrium constants together!

Questions (22)

At equilibrium at a certain temperature, the concentration of NzH3(g), H2(g) and N2(g) are 0.980 M, 1.53 M and 0.510,
1. 1 answer
2. asked by Yassah Kesselly
3. 48 views
at 1500 celcius the system 2NO<-->N2+O2was allowed to come to equilibrium. the equilibrium concentrations were NO=0.00035M
1. 4 answers
2. asked by HELPP ME
3. 558 views
A 0.100 mol sample of H2S is placed in a 10.0 L reaction vessel and heated to 1132°C. At equilibrium, 0.0285 mol H2 is present.
1. 4 answers
2. asked by Linda
3. 3,238 views
Methanol (CH3OH) is produced commercially by the catalyzed reaction of carbon monoxide and hydrogen:CO (g) + 2H2 (g) -> CH3OH
1. 4 answers
2. asked by Anonymous
3. 2,305 views
The value of kp at 20°c for the reaction 2NO(g) + Cl2(g) 2NOCl(g) is 1.9x10^3 atm-1 calculate the value of KC at the same
1. 1 answer
2. asked by Ayan
3. 339 views
A 100 L reaction container is charged with 0.782 mol of NOBr, which decomposes at a certain temperature** (say between 100 and
1. 4 answers
2. asked by JOhn Boku
3. 828 views
At a certain temperature, 0.900 mol of SO3 is placed in a 2.00-L container.2SO3(g)<--> 2SO2(g)+O2(g) At equilibrium, 0.130 mol
1. 6 answers
2. asked by Laura
3. 4,257 views
Using this data,2 NO(g) + Cl2(g) == 2 NOCl(g) Kc = 3.20 X 10-3 NO2(g) == NO(g) + ½ O2(g) Kc = 3.93 calculate a value for Kc for
1. 3 answers
2. asked by Linda
3. 659 views
Determine Kc for the following reaction:1/2N2(g) + 1/2O2(g)+ 1/2Br(g) <-> NOBr(g) from the following information (at 298K)
1. 4 answers
2. asked by K
3. 3,412 views
Can anyone find out if I did it right or not? ThanksA 0.682?g sample of ICl(g) is placed in a 625?mL reaction vessel at 682 K.
1. 5 answers
2. asked by Jasper
3. 1,006 views
what is the value of Kc if PbCl(s)=1.5g, [Pb2+]=1.6*10^-2 M and [Cl-] =3.2*10^-2 M at equilibrium? (The molar mass of PbCl(s) is
1. 2 answers
2. asked by Anonymous
3. 727 views
At some temperature, the reactionPCl3(g)+Cl2(g)====PCl5(g) is at equilibrium when the concentration of PCl3, Cl2, and PCl5 are
1. 4 answers
2. asked by =)
3. 1,002 views
1. A(aq) + B(aq) ¡ê C(aq) + D(aq)Initially, 1 mol of A and 1 mol of B are allowed to react and come to equilibrium. It is
1. 2 answers
2. asked by alyx
3. 928 views
3.9 moles of NO and 0.88 moles of CO2 are allowed to react asNO + CO2 <--> NO2 + CO At equilibrium 0.11 moles of CO2 was
1. 4 answers
2. asked by Ken
3. 520 views
Given the equilibrium constant values:N2 + 1/2O2 >>> N2O ; kc = 2.7 * 10^-18 N2O4>>>>2NO2 kc=4.6*10^-3 1/2N2 + O2>>>NO2 kc = 4.1
1. 4 answers
2. asked by abe
3. 2,044 views
Consider the following equilibrium at 395K:NH4HS(s) <--> NH3(g) + H2S(g) The partial pressure of each gas is 0.265 atm.
1. 3 answers
2. asked by Cami
3. 1,549 views
Given the equation2H^2S(g) <-> 2H^2(g) + S^2(g) With a Kp = 1.2x10^-2 at 1338 Kelvin Find the value of Kc for the reaction
1. 7 answers
2. asked by K
3. 802 views
A 0.100 mol sample of H2S is placed in a 10.0 L reaction vessel and heated to 1132°C. At equilibrium, 0.0285 mol H2 is present.
1. 1 answer
2. asked by Brittany
3. 766 views
at a certain temperature 800 mole of so3 is placed in a 4.00-l container.2SO3(g)<-->2SO2(g)+O2(g) at equilibrium, 0.120 mol of
1. 2 answers
2. asked by Anonymous
3. 628 views
Using this data,2 NO(g) + Cl2(g) == 2 NOCl(g) Kc = 3.20 X 10-3 NO2(g) == NO(g) + ½ O2(g) Kc = 3.93 calculate a value for Kc for
1. 2 answers
2. asked by bob
3. 589 views
10.0 moles of NH3 and 10.0 moles of H2 are introduced into a 1.00 L flask. At equilibrium, 3.0 moles of NH3 gas remain.
1. 2 answers
2. asked by patrick
3. 545 views
Using this data,2 NO(g) + Cl2(g) == 2 NOCl(g) Kc = 3.20 X 10-3 NO2(g) == NO(g) + ½ O2(g) Kc = 3.93 calculate a value for Kc for
1. 1 answer
2. asked by Linda
3. 447 views