posted by HELP ASAP on .
A male cheerleader does 2.25 kJ of work in lifting a 57.5 kg cheerleader 1.25 m off the ground during the half time show. The energy gained by the lifted cheerleader is __________ kJ.
force * distance in direction of force
= 57.5 * 9.81 * 1.25
= 705 Joules = 0.705 kJ
the rest of the 2.25 kJ is lost to heat and his own motion