Posted by **Neo** on Tuesday, July 22, 2014 at 8:12pm.

1. What is the largest integer that is a factor of all three of the following numbers: 2160, 1344, 1440?

a) 6 b) 8 c) 12 d)16 e) none of these

2. The annual income of a family is budgeted as follows:

1/10 for clothing, 1/3 for food, and 1/5 for rent.

This leaves $1320 for other expenses and savings. Find the annual income.

a) $2156 b) $3600 c) $23,760

d) $39,600 e) none of these answers

- Math -
**Reiny**, Tuesday, July 22, 2014 at 10:00pm
2160 = 2*2*2*2*3*3*3*5

1344 = 2*2*2*2*2*2*3*7

1440 = 2*2*2*2*2*3*3*5

HCF = 2*2*2*2*3

= 24

2.

let their income be x

x/10 + x/3 + x/5 + 1320 = x

times 150 , the LCM

15x + 50x + 30x + 198000 = 150x

198000 = 55x

x = 3600

- Math -
**Henry**, Tuesday, July 22, 2014 at 10:01pm
1344 = 1*1344 = 1*2*672 = 1*2*3*224 =

1*2*3*4*56 = 1*2*3*4*7*8.

1440 = 1*1440 = 1*2*720 = 1*2*3*240 =

1*2*3*4*60 = 1*2*3*4*5*12=1*2*3*4*5*6*2

2160 = 1*2160 = 1*2*1080 = 1*2*3*360 =

1*2*3*4*90 = 1*2*3*4*5*18=1*2*3*4*5*6*3

GCF = 4.

2. Income = $X.

(1/10+1/3+1/5)X + 1320 = X

(3/30+10/30*6/30)X + 1320 = x

19x/30 + 1320 = x

Multiply both sides by 30:

19x + 39,600 = 30x

-11x = -39,600

X = $3600

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